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2 years ago

Balance and find out the coefficients of reactions and products

Chemistry

1 answer:

kolezko [41]2 years ago

6 0

Answer:

2, 1, 1, 4.

Explanation:

Hello there!

In this case, for the given chemical reaction:

$H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+H_2O\\$

We can see how there is one SO4 on the left and two on the right, thus, we add a 2 in front of H2SO4:

$2H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+H_2O\\$

Next, since there are 8 atoms of hydrogen on the left and two on the right, we add a 4 in front of H2O to obtain:

$2H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+4H_2O\\$

Which is now balanced so the coefficients 2, 1, 1, 4.

Best regards!

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In the reaction BaCO3 + 2HNO3 + Ba(NO3)2 + CO2 + H2O, what mass of Ba(NO3)2 can be formed by combining 55 g BaCO3 and 26 g HNO3

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<h3>Stoichiometry</h3>

The term stoichiometry refers to mass - volume relationships. Stoichiometry can be used to calculate the amount, mass or volume of reactants and products from the balanced reaction equation.

The equation of the reaction is written as follows;

BaCO3 + 2HNO3 ------> Ba(NO3)2 + CO2 + H2O

Number of moles of BaCO3 = 55 g/197.34 g/mol = 0.28 moles

Number of moles of HNO3 = 26 g/63.01 g/mol = 0.41 moles

From the reaction equation;

1 mole of BaCO3 reacts with 2 moles of HNO3

0.28 moles of BaCO3 reacts with 0.28 moles × 2 moles/1 mole = 0.56 moles

There is not enough HNO3 hence it is the limiting reactant.

Number of moles of Ba(NO3)2 produced is obtained from;

2 moles of HNO3 yields 1 mole of Ba(NO3)2

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= 0.21 moles of Ba(NO3)2

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2 years ago

A sample of PCl5(g) was placed in an otherwise empty flask at an initial pressure of 0.500 atm and a temperature above 500 K. Ov

tia_tia [17]

Answer:

Kp = 0.81666

Explanation:

Pressure of PCl₅ = 0.500 atm

Considering the ICE table for the equilibrium as:

PCl₅ (g) ⇔ PCl₃ (g) + Cl₂ (g)

t = o 0.500

t = eq -x x x

--------------------------------------------- --------------------------

Moles at eq: 0.500-x x x

Given the pressure of PCl₅ at equilibrium = 0.150 atm

Thus, 0.500 - x = 0.150

x = 0.350 atm

The expression for the equilibrium constant is:

$K_p=\frac {P_{PCl_3}P_{[Cl_2}}{P_{PCl_5}}$

So,

$K_p=\frac{x^2}{0.500-x}$

x = 0.350 atm

Thus,

$K_p=\frac{{0.350}^2}{0.500-0.350}$

7 0

3 years ago

Balance and find out the coefficients of reactions and products ​

Balance and find out the coefficients of reactions and products