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Vadim26 [7]
3 years ago
9

The energy a sled has when you pull it back up a hill is best described as

Physics
1 answer:
yawa3891 [41]3 years ago
5 0
The answer is d because you are using energy to pull the sled back up, which is mechanical energy
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Which of the following is not a step toward planning your goals ?​
Simora [160]

Answer:

Disregard a goal if you don't achieve it

Explanation:

This is because in achieving your targets/goals/dreams rewarding yourself for every small accomplishment is very important. It’ll help to keep you motivated and keep your head in the game. Similarly setting short and long-term objectives also plays a vital role. Setting a date is also important because it helps you to put your plan into action. However, disregarding a goal isn’t an option

Please Mark Brainliest If This Helped!

5 0
3 years ago
amelia goes for mountering with some selected friend of her batch .Intially she is scared of it .Her trainer John tells her that
IRISSAK [1]

Answer:

나쁜 소식 원인 나는 ques 원인 메신저 한국어 내가 캔트 unfmder 대답 할 수 없습니

5 0
3 years ago
What is load ?what are the effect of load?
Olegator [25]
Load is the weight exerted by an object to be moved or lifted  
5 0
3 years ago
an 18 ohm resistor and a 6 ohm resistor are connected in parallel to a battery, and the current in the 18 ohm resistor is found
riadik2000 [5.3K]

With 0.45 amp flowing through an 18-ohm resistor, the voltage across it is

       V  =  I R  =  (0.45) x (18)  =  <em>8.1 volts .</em>

"But I asked for the battery voltage!  That's the voltage across the resistor."

The ends of the resistor are connected directly to the battery terminals.
They're the same voltage.

"But what about the 6-ohm resistor ?  Where does that figure in ?"

In parallel, it doesn't.  It's also connected directly across the battery,
and it has its own current. 

In parallel, neither resistor knows or cares whether or not there are
any other resistors present.  In parallel, it makes no dif.


3 0
3 years ago
The solid right-circular cylinder of mass 500 kg is set into torque-free motion with its symmetry axis initially aligned with th
aivan3 [116]

Answer:

30.95°

Explanation:

We need to define the moment of inertia of cylinder but in terms of mass, that equation say,

A=\frac{1}{12}m(3r^2+l^2)

Replacing the values we have,

A=\frac{1}{12}(500)(3(0.5)^2+(2)^2)A=197.9kg.m^2

At the same time we can calculate the mass moment of intertia of cylinder but in an axial way, that is,

c=\frac{1}{2}mr^2

c=\frac{1}{2}(500)(0.5)^2

c=62.5kg.m^2

Finally we need to find the required angle between the fixed line a-a (I attached an image )

\Phi = 2tan^{-1}\sqrt{\frac{(\frac{A}{cos\gamma})^2-A^2}{c^2}}

Replacing the values that we have,

\Phi = 2tan^{-1}\sqrt{\frac{(\frac{197.9}{cos5\°})^2-197.9^2}{62.5^2}}

\Phi = 2tan^{-1}(\sqrt{0.076634})

\Phi = 2tan^{-1}(0.2768)

\Phi = 2(15.47)

\Phi = 30.95\°

4 0
4 years ago
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