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s344n2d4d5 [400]
3 years ago
10

A very loud train whistle has an acoustic power output of 100 W. If the sound energy spreads out spherically, what is the intens

ity level in dB at a distance of 100 meters from the train?
Physics
1 answer:
valentina_108 [34]3 years ago
7 0

Answer

given,

Power output of loud train = 100 W

Distance of intensity level from train= 100 m

I₀ = 10⁻¹² W/m²                      

Intensity of sound = ?        

we know,                            

I = \dfrac{P}{Area}          

I = \dfrac{P}{4\pi r^2}          

I = \dfrac{100}{4\pi 100^2}          

I =7.957\times 10^{-4}\ W/m^2

Intensity level                              

  = 10 log(\dfrac{I}{I_0})

  = 10 log(\dfrac{7.975\times 10^{-4}}{10^{-12}})

  = 10 \times 8.900

  = 89 dB

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a) We kindly invite you to see the explanation and the image attached below.

b) The acceleration of the masses is 4.203 meters per square second.

c) The tension force in the cord is 28.02 newtons.

d) The system will take approximately 0.845 seconds to cover a distance of 1.5 meters.

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T - Tension force in the cord, measured in newtons.

m_{A}, m_{B} - Masses of blocks A and B, measured in kilograms.

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a - Net acceleration of the each block, measured in meters per square second.

By subtracting (2) by (1), we get an expression for the acceleration of each mass:

m_{B}\cdot a +m_{A}\cdot a = T-m_{B}\cdot g -T + m_{A}\cdot g

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c) From (2) we get the following expression for the tension force in the cord:

T = m_{B}\cdot (a+g)

If we know that m_{B} = 2\,kg, g = 9.807\,\frac{m}{s^{2}} and a = 4.203\,\frac{m}{s^{2}}, then the tension force in the cord:

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a - Net acceleration, measured in meters per square second.

t - Time, measured in seconds.

\Delta y - Covered distance, measured in meters.

If we know that a = 4.203\,\frac{m}{s^{2}} and \Delta y = 1.5\,m, then the time taken by the system is:

t = \sqrt{\frac{2\cdot \Delta y}{a} }

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The system will take approximately 0.845 seconds to cover a distance of 1.5 meters.

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