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Yakvenalex [24]
2 years ago
13

What is the great egg drop experiment about?

Physics
2 answers:
Burka [1]2 years ago
7 0

Answer:

The egg drop experiment is about building a structure around an egg with different materials so that when it is dropped from a high place it doesn't break.

Explanation:

I have done this experiment before so I know. Have a cool awesome great splendid Supercalifragilisticexpialidocious day ok bye.

kondaur [170]2 years ago
6 0
Whichever person or group can build something to protect the egg from cracking when it is dropped from a high spot without it breaking or cracking wins
You might be interested in
What unita are used to measure electrical current​
JulijaS [17]

Answer:

It's called an ampere!

Explanation:

The SI unit of electric current is the ampere, which is the flow of electric charge across a surface at the rate of one coulomb per second. The ampere (symbol: A) is an SI base unit Electric current is measured using a device called an ammeter.

Hope this helps :)

4 0
3 years ago
Read 2 more answers
how did we discover how to brake the sound barior and why did we not go as fast as the speed of light
quester [9]

The problem of the "sound barrier" has to do with moving through
air, and the things the air does when you try to push it out of the
way faster than the speed of sound.  Moving through air faster
than sound was an engineering and technological problem, not
a scientific one.

Concerning light, that's about 874 thousand times faster. 
See the problem ?

4 0
2 years ago
If carbon has an atomic number of 6, how many protons and neutrons are found in the carbon-14 atom? A.
Alex Ar [27]
The correct answer is B. 6 protons and 8 neutrons

Carbon-14 has same atomic number of 6. It has a nucleon number of 14
Atomic number = proton number = 6
Neutron number = nucleon number - atomic number = 14 - 6 = 8

Hope it helped!
5 0
3 years ago
1. A truck with a mass of 8, 000 kg is traveling at 26.8 m/s when it hits the brakes. A.)What is the momentum of the truck befor
NikAS [45]

Answer:

1. A.) The moment of the truck before it hits the brakes is 214,400 kg·m/s

B.) The force it takes to stop the truck is approximately 17,290.4 N

Explanation:

1. A.) The given parameters are;

The mass of the truck, m = 8,000 kg

The velocity of the truck when it hits the brakes, u = 26.8 m/s

Momentum = Mass × Velocity

The moment of the truck = The mass of the truck × The velocity of the truck

Therefore;

The moment of the truck before it hits the brakes = 8,000 kg × 26.8 m/s = 214,400 kg·m/s

B.) The amount of momentum lost when the truck comes to a stop = The initial momentum of the truck

The time it takes the truck to come to a complete stop, t = 12.4 s

The deceleration, "a" of the truck is given by the following kinematic equation of motion

v = u - a·t

Where;

v = The final velocity of the truck = 0 m/s

u = The initial velocity = 26.8 m/s

a = the deceleration of the truck

t = The time of deceleration of the truck = 12.4 s

Substituting the known values gives;

0 = 26.8 - a × 12.4

Therefore;

26.8 = a × 12.4

a = 26.8/12.4 ≈ 2.1613

The deceleration (negative acceleration) of the truck, a ≈ 2.1613 m/s²

Force = Mass × Acceleration

The force required to stop the truck = The mass pf the truck × The deceleration (negative acceleration) given to the truck

∴ The force it takes to stop the truck = 8,000 kg × 2.1613 m/s² ≈ 17,290.4 N.

8 0
3 years ago
The element in an incandescent light bulb that releases light energy is
Leviafan [203]
A thin tungsten filament
5 0
3 years ago
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