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ratelena [41]
3 years ago
10

A scooter traveling at 4 m/s rides 800 meters. For what duration of time has the scooter been traveling?

Physics
2 answers:
rosijanka [135]3 years ago
8 0

Answer:

<h3>The answer is 200 s</h3>

Explanation:

To find the duration or time taken we use the formula

t  = \frac{d}{v}  \\

where

d is the distance

v is the velocity

From the question

d = 800 m

t = 4 m/s

We have

t =  \frac{800}{4}  \\

We have the final answer as

<h3>200 s</h3>

Hope this helps you

strojnjashka [21]3 years ago
3 0

200secs

The equation is Distance ÷ speed = time so, 800m ÷ 4m/s = 200 secs.

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The tension of a guitar string is increased by 40%. By what factor odes the fundamental frequency of vibration change? a. 1.13 b
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Answer:

<h3> b. 1.18</h3>

Explanation:

The fundamental frequency in string is expressed as;

F1 = 1/2L√T/m .... 1

L is the length of the string

T is the tension

m is the mass per unit length

If the tension is increased by 40%, the new tension will be;

T2 = T + 40%T

T2 = T + 0.4T

T2 = 1.4T

The new fundamental frequency will be;

F2 = 1/2L√1.4T/m ..... 2

Divide 1 by 2;

F2/F = (1/2L√1.4T/m)/1/2L√T/m)+

F2/F = √1.4T/m ÷ √T/m

F2/F = √1.4T/√m ×√m/√T

F2/F = √1.4T/√T

F2/F = 1.18√T/√T

F2/F = 1.18

F2 = 1.18F

Hence the fundamental frequency of vibration changes by a factor of 1.18

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A materials density is the same , no matter how large or small the sample is or what it’s shape is as long as it is solid unifor
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Answer:

See the explanation below

Explanation:

Density is defined as the relationship between mass and volume, i.e. the following equation can be used:

density = m/v

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density [kg/m^3]

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v = volume [m^3]

If we change the volume of a body by reducing its size, its mass will also decrease proportionally with a density as seen in the equation.

m = density*v

To understand this concept more clearly, let's use the following example:

We know that the density of water is equal to 1000 [kg/m^3], that is, 1 cubic meter of water contains 1000 kilograms of water, using the equation.

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m = 1000*1 = 1000 [kg]

Now if we have 500 kilograms of water, that would pass with the volume so that the density remains constant.

1000 = 500/v

v = 500/1000

v = 0.5 [m^3]

We can see that the volume of water has halved. Since the mass of water was reduced by half. That is, the relationship between mass and volume is proportional to the density of the material or substance.

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