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3 years ago

A scooter traveling at 4 m/s rides 800 meters. For what duration of time has the scooter been traveling?

Physics

2 answers:

rosijanka [135]3 years ago

8 0

Answer:

<h3>The answer is 200 s</h3>

Explanation:

To find the duration or time taken we use the formula

$t = \frac{d}{v} \\$

where

d is the distance

v is the velocity

From the question

d = 800 m

t = 4 m/s

We have

$t = \frac{800}{4} \\$

We have the final answer as

Hope this helps you

strojnjashka [21]3 years ago

3 0

200secs

The equation is Distance ÷ speed = time so, 800m ÷ 4m/s = 200 secs.

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10 months ago

A 1000kg car is rolling slowly across a level surface at 1 m/s heading twoards a group o fsmall innocent children. The doors are

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Answer:

The force required to push to stop the car is 288.67 N

Explanation:

Given that

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$W=\dfrac{1}{2}m(v^2-u^2)F\times d=\dfrac{1}{2}m(v^2-u^2)$

$v = 0$

$Fd\ cos\theta=\dfrac{1}{2}m(u^2) F=\dfrac{\dfrac{1}{2}m(u^2)}{d\ cos\theta}F=\dfrac{\dfrac{1}{2}\times 1000\times (1)^2}{2\ cos(30)}F = -288.67 N$

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3 0

2 years ago

An umbrella tends to move upward on a windy day because _____.

masha68 [24]

E. all of the above

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2 years ago

Two objects are dropped from rest from the same height. Object A falls through a distance Da and during a time t, and object B f

stiv31 [10]

Answer:

Da=(1/4)Db

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

When s = Da, t = t

$s=ut+\frac{1}{2}at^2\\\Rightarrow Da=0\times t+\frac{1}{2}\times a\times t^2\\\Rightarrow Da=\frac{1}{2}at^2$

When s = Db, t = 2t

$s=ut+\frac{1}{2}at^2\\\Rightarrow Da=0\times t+\frac{1}{2}\times a\times (2t)^2\\\Rightarrow Db=\frac{1}{2}a4t^2$

Dividing the two equations

$\frac{Da}{Db}=\frac{\frac{1}{2}at^2}{\frac{1}{2}a4t^2}=\frac{1}{4}\\\Rightarrow \frac{Da}{Db}=\frac{1}{4}\\\Rightarrow Da=\frac{1}{4}Db$

Hence, Da=(1/4)Db

3 0

3 years ago