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3 years ago

1. A mass is on a level plane, it has a weight of 20N. What is the coefficient of kinetic friction if an applied force

Physics

1 answer:

Arturiano [62]3 years ago

4 0

Answer:

0.4

Explanation:

F-Fr=ma where F is applied force, Fr is friction, m is mass and a is acceleration.

Since the mass is moving with a constant velocity, there's no acceleration hence

$F=Fr=\mu N$ where N is the weight of object and \mu is coefficient of kinetic friction.

$F=\mu N and making [tex]\mu$ the subject

$\mu=\frac {F}{N}$

Substituting F for 8 N and N for 20 N

$\mu=\frac {8}{20}=0.4$

Therefore, coefficient of kinetic friction is 0.4

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Europe and North America are moving apart by about 5 m per century. As the continents separate, new ocean floor is created along

Alinara [238K]

Answer:

Area = 25km² in a century.

Explanation:

Given

Spread Rate = 5m/century

Length of rift = 5000km

Convert to metres

Length of rift = 5000 * 1000m

Length of rift = 5,000,000m

In one century, the additional area to Atlantis = (Rift Length) * (Spread rate) * 1 century

Atea = 5,000,000 m * 5m/century * 1 century

Area = 25,000,000m² in a century

----- Convert to km²

Area = 25,000,000km² * 1m²/1,000,000km²

Area = 25km² in a century.

Hence, the total area of new ocean floor created in the Atlantic each century is 25km²

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3 years ago

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Anastaziya [24]

Answer:

Explanation:

The formula to analyze motion in the vertical (or y) dimension is

$A_y=Asin\theta$ which says that the motion in the y-dimension is equal to the magnitude of the A vector times the sin of the angle.

The formula to analyze motion in the horizontal (or x) dimension is

$A_x=Acos\theta$ which says that the motion in the x-dimension is equal t the mignitude of the A vector times the cosine of the angle.

Many times this is used to find the upwards velocity and the horizontal velocity when an overall velocity is given with an angle of inclination.

3 0

3 years ago

The top of a ladder slides down a vertical wall at a rate of 0.125 m/s. at the moment when the bottom of the ladder is 5 m from

Contact [7]

Vertically (y-axis), horizontally(x-axis)

dy/dt = -0.125 m/s (-ve since y decreasing )

dx/dt = +0.3 m/s (+ve, x increases)

and, x = 5 m

length of the ladder = k (a constant)

k^2 = x^2 + y^2

differentiating it wrt t,

0 = 2x dx/dt + 2y dy/dt

0 = 2(5)(0.3) + 2(y)(-0.125)

y = 12

which means, when the bottom of the ladder is 5m from the wall, the top of the ladder is 12m from the bottom.

thus, k^2 = 5^2 + 12^2

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5 0

3 years ago

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GenaCL600 [577]

Answer:cells?

Explanation:

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6 0

3 years ago

A 75 kg baseball player runs at a velocity of 6 m/s and sliding 2 m what is the force of friction that acts upon him?

Maslowich

Answer:

1350N

Explanation:

Given data

mass= 75kg

velocity= 6m/s

distance= 2m

The expression for the applied force is given as

F= mv^2/d

Substitute

F= 75*(6)^2/ 2

F= 75*36/2

F= 2700/2

F= 1350N

Hence the force is 1350N

6 0

3 years ago