Answer:
-.457 m/s^2
Explanation:
Actual weight = 60 .3 (9.81) = 591.54 N
Accel of lift changes this to 60.3 ( 9.81 - L) where L - accel of lift
60.3 ( 9.81 - L ) = 564
solve for L = .457 m/s^2 DOWNWARD
so L = - .457 m/s^2
The working distance gets shorter as the magnification gets bigger. In order to focus, the high-power objective lens must be significantly nearer to the specimen than the low-power lens. Magnification is negatively correlated with working distance.
Magnification change The magnification of a specimen is increased by switching from low power to high power. The magnification of an image is determined by multiplying the magnification of the objective lens by the magnification of the ocular lens, or eyepiece.
The geometry of the optical system connects the magnifying power, or how much the thing being observed seems expanded, and the field of view, or the size of the object that can be seen.
To know more about working distance
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Answer:
(b)
Explanation:
The voltage always lags the current by 90°, regardless of the frequency.
<h3>
Answer:</h3>
30.4 km/hr
<h3>
Explanation:</h3>
<u>We are given</u>;
- Speed in the first 2 hours as 25 km/hr
- Speed in the next 3 hours as 34 km/hr
We are required to determine the average velocity in km/hr
- To get the average velocity we divide total distance by total time.
- Thus, we need to determine the total distance
Distance = Speed × time
Distance covered in the first 2 hours;
= 25 km/hr × 2 hours
= 50 km
Distance in the next 3 hours
= 34 km/hr × 3 hours
= 102 km
Therefore, total distance = 50 km + 102 km
= 152 km
Total time = 2 hrs + 3 hrs
= 5 hours
Therefore;
Average speed = 152 km ÷ 5 hours
= 30.4 km/hr
Thus, the average speed is 30.4 km/hr
