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Jet001 [13]
3 years ago
6

For the reaction below, if the rate of appearance of Br2 is 0.180 M/s, what is the rate of disappearance of

Chemistry
1 answer:
brilliants [131]3 years ago
7 0

Answer:

–0.360 M/s

Explanation:

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2. Which is a true statement about a zero net force?
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Answer: the correct option is A (A zero net force causes no change to an object's

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Explanation:

Force is a vector quantity that causes an object to accelerate or change velocity when pushed or pulled. While a NET FORCE can be defined as the combination of all forces acting on an object which is equally capable of accelerating the object.

When a NET FORCE is equal to zero( that is zero net force),there will be no change to an object's motion. When the net force of an object is equal to zero , it shows the object is in either static equilibrium( the objects velocity is zero) or dynamic equilibrium(where the object is moving at constant velocity). In both cases, the object remains motionless because the net forces is equal to zero.

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4 years ago
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Question 1 (1 point)
andriy [413]

Answer:

The answer would be:

It becomes unstable.

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On average, one chlorine atom can destroy 100,000 ozone molecules. Such destructive power is tremendous when it is related to th
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One of the particles in an atom is the proton. A proton has a radius of
Charra [1.4K]

Answer:

Density = 4.06 * 10^14

Explanation:

Givens

r = 1 * 10^-13 cm

m = 1.7 * 10^-24 grams

Formula

V = 4/3 * pi * r^3

D = m/V

Solution

Put the givens into the formula.

V = (4/3) 3.14 * (1 * 10^-13)^3          Find the value for r^3

V = (4/3) 3.14 * 1 * 10^-39               Find the volume. Indicate divide by 3

V = 1.256 10^-38/3

V = 4.1867 * 10^-39

Density = m / v

Density = 1.7*10^-24/4.1867*10^-39  Do the division

Density = .406 * 10^(-24 + 39)

Density = .406 * 10^15 grams/ cm^3

Answer: Density = 4.06 * 10^14

5 0
2 years ago
How many more atoms are there in 48g of C compared with 48.6g of Mg? Explain your answer.
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Answer:

The number of carbon atoms is twice the number of magnesium atoms

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