Answer:
The minimum coefficient of friction is 0.544
Solution:
As per the question:
Radius of the curve, R = 48 m
Speed of the car, v = 16 m/s
To calculate the minimum coefficient of static friction:
The centrifugal force on the box is in the outward direction and is given by:

where
= coefficient of static friction
The net force on the box is zero, since, the box is stationary and is given by:
Answer:
<em>option</em><em> A</em>
Explanation:
the diameter is twice the length of the radius
hope it helps
When an electron stops, it emits a photon with energy equal to the kinetic energy lost by the electron:

The energy of the photon is

where

is the Planck constant and f is the frequency. Therefore, the maximum frequency of the emitted photon occurs when the loss of kinetic energy is maximum.
The maximum loss of kinetic energy of the electron occurs when the electron stops completely, so it loses all its energy:

Keeping in mind that

, we have

And so, this corresponds to the energy of the emitted photon, E. Therefore, we can find the maximum frequency of the emitted photon:
Explanation:
The cross section per unit length is uniform, so ρ is constant.
The center of mass is therefore:
x_avg = (∫₀ᴸ x ρ dL) / (∫₀ᴸ ρ dL)
x_avg = (∫₀ᴸ x dL) / (∫₀ᴸ dL)
x_avg = (½ L²) / (L)
x_avg = ½ L