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snow_tiger [21]
4 years ago
14

Materials of low mass are combined to form a substance of higher mass during ____. a. fission c. both A and B b. fusion d. neith

er A nor B Please select the best answer from the choices provided
Chemistry
1 answer:
Andrei [34K]4 years ago
7 0
<h2>The required "option is b) Fusion"</h2>

Explanation:

  • During fission, the nucleus of higher mass is broken down into the nucleus of lower mass in which a high amount of energy is released.
  • During fusion two nuclei combine or fuses to form a larger molecule of higher mass for which a high amount of energy is provided.
  • Therefore, the higher mass of a substance is formed with the combination of lower mass of a substance during the process of fusion.
  • Hence, the required option is Fusion.
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For each solute, identify the better solvent: water or carbon tetrachloride
Rom4ik [11]

The better solvent for Na₂S (Natrium sulfide)and CH₃OH(methanol): water

The better solvent for C₆H₆(benzene) and Br₂(bromine) : CCl₄

<h3>Further explanation</h3>

In covalent bonds there are differences in electronegativity which causes polarization of the bonds

If the bond in an electron pair is more attracted to one atom, then the covalent bond is polar

This is due to the electron attraction of one atom which is bigger than the other atoms

But the geometrical shape of molecules can make molecules that have polar bonds can be polar or non-polar

The symmetrical shape of the molecule is usually a non-polar molecule

For example on H₂O

This molecule is polar because of the difference in electronegativity where the O atom has a stronger electron attraction when compared to the H atom, so this molecule have positive and negative poles where the negative pole is on the O atom

Polar molecules dissolved in water undergo ionization so they can conduct electricity and are electrolyte,  while non-polar molecules are non-electrolyte.

<em>Polar molecules will dissolve polar molecules and vice versa non-polar molecules can dissolve non-polar molecules. </em>

So water molecules that can be used to test polar and non-polar molecules by dissolving them in water

The size of polarity is usually indicated by the magnitude of the dipole moment

The greater the dipole moment, the more polar the compound is. In non-polar compounds the dipole moment is zero.

water- H₂O is a polar solvent, due to the large electronegativity between O and H atoms, and the shape of the V molecule (asymmetrical)

CCl₄- Carbon tetrachloride is a nonpolar solvent, where C atoms as central and Cl atoms have different electronegativity but because of the symmetrical shape so that the dipole moment is removed and so it is nonpolar

Let see that each of these compounds is polar or non-polar

Na₂S (Natrium sulfide)and CH₃OH(methanol) are ion compounds that can dissolve in polar solvents such as water

C₆H₆(benzene) and Br₂(bromine) are non-polar covalent compounds with symmetrical shapes and do not have free electron pairs that can dissolve in CCl₄

<h3 /><h3>Learn more</h3>

ionic bonding

brainly.com/question/1603987

type of chemical bond

brainly.com/question/5008811

Lewis structures

brainly.com/question/6085185

Keywords : chemical bond, covalen bond, water, electrons, dipole moment

<h3 />

4 0
3 years ago
Read 2 more answers
If 25.0 mL of 0.451 M NaOH solution is titrated with 0.253 M H2SO4, the flask at the endpoint will contain (besides the indicato
tigry1 [53]

Answer:

H₂O, Na⁺, and SO₄²⁻

Explanation:

NaOH and H₂SO₄ are strong electrolytes. They will ionize completely .

Molecular equation:          2NaOH + H₂SO₄ ⟶ Na₂SO₄ + 2H₂O

Ionic equation: 2Na⁺ + 2OH⁻ + 2H⁺ + SO₄²⁻ ⟶  2Na⁺ + SO₄²⁻+ 2H₂O

  • The concentration of water is 55.5 mol·L⁻¹.
  • The concentration of Na⁺ is twice that of SO₄²⁻ .
  • Hydrolysis of SO₄²⁻ is negligible.

The principal components in the flask at the endpoint are H₂O, Na⁺, and SO₄²⁻.

4 0
3 years ago
A line in the Brackett series of hydrogen has a wavelength of 1945 nm. From what state did the electron originate?
fiasKO [112]
Rydberg Eqn is given as:
 1/λ = R [1/n1^2 - 1/n2^2] 
<span>Where λ is the wavelength of the light; 2626 nm = 2.626×10^-6 m </span>
<span>R is the Rydberg constant: R = 1.09737×10^7 m-1 </span>
<span>From Brackett series n1 = 4 </span>
<span>Hence 1/(2.626×10^-6 ) = 1.09737× 10^7 [1/4^2 – 1/n2^2] </span>
<span>Some rearranging and collecting up terms: </span>
<span>1 = (2.626×10^-6)×(1.09737× 10^7)[1/16 -1/n2^2] </span>
<span>1= 28.82[1/16 – 1/n2^2] </span>
<span>28.82/n^2 = 1.8011 – 1 = 0.8011 </span>
<span>n^2 = 28.82/0.8011 = 35.98 </span>
<span>n = √(35.98) = 6</span>
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3 years ago
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6 0
3 years ago
H2 is an example of? A. a molecule B. an element or C. both a molecule and an element.
pashok25 [27]

It is an element

It is a molecule

7 0
3 years ago
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