Answer:
I2>I1
Explanation:
This problem can be solved by using the parallel axis theorem. If the axis of rotation of a rigid body (with moment of inertia I1 at its center of mass) is changed, then, the new moment of inertia is gven by:

where M is the mass of the object and d is the distance of the new axis to the axis of the center of mass.
It is clear that I2 is greater than I1 by the contribution of the term Md^2.
I2>I1
hope this helps!!
The gravitational potential energy will increase
Explanation:
The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in a gravitational field.
Near the Earth's surface, the GPE of an object is given by

where
m is the mass of the object
g is the acceleration of gravity
h is the heigth of the object above the ground
From the equation, we see that the GPE is directly proportional to the mass: therefore, if the mass increases, the GPE will increase as well.
So, for the beanbag in this problem, when its mass increases, the GPE will increase as well.
Learn more about gravitational potential energy:
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We have that F=ma from the 2nd Newton law where F is the force, m is the mass and a is the acceleration. Suppose we have that F' is the new force and m' is the new mass. Then, we have that a'=F'/m' still, by rearranging Newton's law. We are given that F'=2F and m'=m/2. Hence,

But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.
Is their a multiple choice to choose from I'm not sure the answer I got is even right.
That would be very helpful.