Answer:
Step-by-step explanation:
xy = 300
x + y = 50 Solve for y
y = 50 - x substitute into xy = 300
x(50 - x) = 300 Remove the brackets.
50x - x^2 = 300 Bring the left to the right.
0 = x^2 - 50x + 300
This is a quadratic. It will have 2 solutions.
a=1
b = - 50
c = 300
Put these into the quadratic equation.
It turns out that x has two values -- both plus
x1 = 42.03
x2 = 6.97
x1 + y1 = 50
42.03 + y = 50
y = 50 - 42.03
y = 7,97
(42.03 , 7.97)
====================
x2 + y2 = 50
6.97 + y2 = 50
y2 = 50 - 6.97
y2 = 43.03
(6.97 , 43.03)
Look at the formula A = b(h): Area of a rect. = base times height.
In the unusual situation where you'd hold the area constant and vary b and h, then A=bh could be re-written as
A
---- = h or A/h = b. In both cases we'd be working with inverse proportion,
b not direct proportion / variation.
Answer:
4/5
Step-by-step explanation:
formula for slope is (y2-y1)/(x2-x1)
I believe the word you are looking for is variable. variable is the word used when talking about a value of x in an equation.
Pretty sure it’s the second one
