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pychu [463]
3 years ago
5

What would you do to improve the precision of an experiment?

Physics
2 answers:
REY [17]3 years ago
8 0

Answer:

The precision of an experiment is the condition where an experiment is very accurate and correct by performing various types of experiments. Some of the steps in improving the precision of an experiment are as follows-

1) Observations must be clearly made

2) Collecting data to the related problems or prior experiment analysis

3) Making proper use of the equipment (instruments)

4) Making a hypothesis on the basis of collected data

5) For precision, the test/experiments should be made with proper sample size.

6) Errors related to instruments and experimental errors should be reduced.

7) In some experiments, parallax must also be reduced.

GenaCL600 [577]3 years ago
5 0

Explanation:

Precision represents that how close the different measurements of the sample one take are to one another.

  • One can increase the precision in lab by paying attention to each and every detail.
  • Usage of the equipment properly and also increasing the sample size.
  • Ensuring that the equipment is calibrated properly. They should be clean and functioning. Using equipment which is not functioning correctly can cause results to swing wildly and also bits of the debris stuck to the equipment can influence the measurements of the mass and the volume.
  • Each measurement must be taken multiple times, especially if experiments in which combining of the substances in specific amounts is involved.
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Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia
Mademuasel [1]

Answer:

91.5 km

Explanation:

Hi!

If we are to ignore the variation in gravity we can use the formula for teh potential energy near the surface of a planet:

mgh

If the energy of the material ejected from the volcano on Io's surface is the same on earth's surface we have:

mg_{Io}h_{Io} =mg_{e}h_{e}

where subindexes Io and e means Jupiter's moon Io, and Earth, respectively

solving for h_e

h_{e} = h_{Io} \frac{g_{e}}{g_{Io}}

The acceleration due to the gravity of a planet can be calculated as:

g = G \frac{m}{R^2}

Where R and m are the radius  and mass of the planet

Therefore:

h_{e} = h_{Io} (\frac{m_{Io}}{m_e})(\frac{R_e}{R_{Io}})^2

m_e = 5,972 × 10^24 kg

R_e = 6 371 km

Replacing all given values:

h_e = 500 km *(0.183) = 91.515 990 km

7 0
3 years ago
What is the kinetic energy of a 620.0 kg roller coaster moving with a velocity of 9.00 m/s?
Darina [25.2K]
The kinetic energy of a moving object is calculated through the equation,
                         KE = 0.5mv²
where m is the mass and v is the velocity. 
Substituting the known values,
                         KE = 0.5(620 kg)(9 m/s)²
                           KE = 25,110 J
Thus, the kinetic energy is equal to 25,110 J. 
3 0
3 years ago
Read 2 more answers
a concave lens creates a virtual image at -47.0 cm and a magnification of +1.75. what is the focal length?
Lilit [14]

The focal length of given concave lens will be -26.85 cm

The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.

Given  concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.

We have to find focal length

The focal length can be found out by following way:

Magnification = m = +1.75

m = hi/h

hi = -47 cm

1.75 = -47/h

h = -26.85 cm

So the focal length of given concave lens will be -26.85 cm

Learn more about magnification factor here:

brainly.com/question/6947486

#SPJ10

8 0
1 year ago
Unlike fossil fuels, biomass fuels _____.
dezoksy [38]

the answer is B- are renewable resources

7 0
3 years ago
Read 2 more answers
Uma carga puntiforme de + 3,0uC é colocada em um ponto P de um campo elétrico gerado por uma partícula eletrizada com carga desc
expeople1 [14]

Responda:

1) E = 6 × 10 ^ 6NC ^ -1 2) Q = 6 × 10 ^ -5

Explicação:

Dado o seguinte:

Carga (q) = 3uC = 3 × 10 ^ -6C

Força elétrica (Fe) = 18N

Intensidade do campo elétrico (E) =?

1)

Lembre-se:

Força elétrica (Fe) = carga (q) * Intensidade do campo elétrico (E)

Fe = qE; E = Fe / q

E = 18N / (3 × 10 ^ -6C)

E = 6N / 10 ^ -6C

E = 6 × 10 ^ 6NC ^ -1

2)

Lembre-se:

E = kQ / r ^ 2

E = intensidade do campo elétrico

Q = carga de origem

r = distância de espera = 30cm = 30/100 = 0,3m

K = 9,0 × 10 ^ 9

6 × 10 ^ 6 = (9,0 × 10 ^ 9 * Q) / 0,3 ^ 2

9,0 × 10 ^ 9 * Q = 6 × 10 ^ 6 * 0,09

Q = 0,54 × 10 ^ 6 / 9,0 × 10 ^ 9

Q = 0,06 × 10 ^ (6-9)

Q = 0,06 × 10 ^ -3

Q = 6 × 10 ^ -5 = 60 × 10 ^ -6 = 60μC

7 0
3 years ago
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