Answer:
91.5 km
Explanation:
Hi!
If we are to ignore the variation in gravity we can use the formula for teh potential energy near the surface of a planet:
mgh
If the energy of the material ejected from the volcano on Io's surface is the same on earth's surface we have:

where subindexes Io and e means Jupiter's moon Io, and Earth, respectively
solving for h_e

The acceleration due to the gravity of a planet can be calculated as:

Where R and m are the radius and mass of the planet
Therefore:

m_e = 5,972 × 10^24 kg
R_e = 6 371 km
Replacing all given values:
h_e = 500 km *(0.183) = 91.515 990 km
The kinetic energy of a moving object is calculated through the equation,
KE = 0.5mv²
where m is the mass and v is the velocity.
Substituting the known values,
KE = 0.5(620 kg)(9 m/s)²
KE = 25,110 J
Thus, the kinetic energy is equal to 25,110 J.
The focal length of given concave lens will be -26.85 cm
The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.
Given concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.
We have to find focal length
The focal length can be found out by following way:
Magnification = m = +1.75
m = hi/h
hi = -47 cm
1.75 = -47/h
h = -26.85 cm
So the focal length of given concave lens will be -26.85 cm
Learn more about magnification factor here:
brainly.com/question/6947486
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the answer is B- are renewable resources
Responda:
1) E = 6 × 10 ^ 6NC ^ -1 2) Q = 6 × 10 ^ -5
Explicação:
Dado o seguinte:
Carga (q) = 3uC = 3 × 10 ^ -6C
Força elétrica (Fe) = 18N
Intensidade do campo elétrico (E) =?
1)
Lembre-se:
Força elétrica (Fe) = carga (q) * Intensidade do campo elétrico (E)
Fe = qE; E = Fe / q
E = 18N / (3 × 10 ^ -6C)
E = 6N / 10 ^ -6C
E = 6 × 10 ^ 6NC ^ -1
2)
Lembre-se:
E = kQ / r ^ 2
E = intensidade do campo elétrico
Q = carga de origem
r = distância de espera = 30cm = 30/100 = 0,3m
K = 9,0 × 10 ^ 9
6 × 10 ^ 6 = (9,0 × 10 ^ 9 * Q) / 0,3 ^ 2
9,0 × 10 ^ 9 * Q = 6 × 10 ^ 6 * 0,09
Q = 0,54 × 10 ^ 6 / 9,0 × 10 ^ 9
Q = 0,06 × 10 ^ (6-9)
Q = 0,06 × 10 ^ -3
Q = 6 × 10 ^ -5 = 60 × 10 ^ -6 = 60μC