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Dovator [93]
3 years ago
10

Find the slope of the line perpendicular to the line x cos alpha + y Sin Alpha = p​

Mathematics
1 answer:
ivanzaharov [21]3 years ago
7 0

Answer:

The slope of the line perpendicular to the line x cos α + y sin α = p is  tanα .

Step-by-step explanation:

Given equation of line as :

x cos α + y sin α = p

The standard equation of line is given as

y = m x + c

where m is the slope of the line

Now, for line x cos α + y sin α = p

Or, y sin α = p -  x cos α

or,  y sin α = -  x cos α + p

Or, y = - \dfrac{\textrm cos\alpha }{\textrm sin\alpha } x + \dfrac{\textrm p}{\textrm sin\alpha }

Or, y = - cotα x +p cosecα

So By comparing the line, the slope of this line = m = - cotα

Now, when two lines are perpendicular then

The product of the slope of lines = - 1

Let the slope of other line = M

So, from property

m × M = - 1

∴ M = \frac{-1}{m}

Or, M = \frac{-1}{-cot\alpha }

∴ M = tanα

So, slope of line perpendicular to given line = M =  tanα

Hence The slope of the line perpendicular to the line x cos α + y sin α = p is  tanα . Answer

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