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-BARSIC- [3]
3 years ago
9

Use the distributive property to write an expression equivalent to 5x (3+4)

Mathematics
2 answers:
Law Incorporation [45]3 years ago
8 0
You can solve it algebraically by simply adding the numbers in the parenthesis and multiplying to get 35x but if you want to solve it using distributive property exclusively then distribute as so

5x(3) + 5x(4)

15x + 20x

35x
Inessa [10]3 years ago
8 0
Easy first brackets
So (3+4)=(7)
So 5x(7)= 35x because she whatever is on the outside should be multiplied by the number in the brackets
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Please someone help me with this
shtirl [24]

Answer:

2,-1.5

Step-by-step explanation:

To find the midpoint of a line segment, take the average of the x coordinates and y coordinates of the two points that make it up.

\frac{2+2}{2} ,\frac{4+(-7)}{2}

=\frac{4}{2} , \frac{-3}{2}\frac{4}{2} , \frac{-3}{2}

=2,-1.5

7 0
3 years ago
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A. A mother dolphin is 150.25 meters below sea level. Her calf is 45 meters below sea level.
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Idk

Step-by-step explanation:

8 0
3 years ago
Three times the sum of a number and seven is negative thirty-six. What is the number?
Katarina [22]

Answer:

n =-19

Step-by-step explanation:

3* (n+7) = -36

Distribute

3n+21 = -36

Subtract 21 from each side

3n+21-21 = -36-21

3n = -57

Divide by 3

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7 0
3 years ago
Read 2 more answers
Mrs. Oliver drew a box plot to represent her students’ scores on a mid-term test.
Rzqust [24]

Answer:

About 1/4 scored higher and 3/4 scored lower

Step-by-step explanation:

84 is on the right side line

Each line represents 25 % of the score

It is 75 percent ( 3 lines) of the way

She scored higher than 75% of the students and lower than 25% of the students

About 1/4 scored higher and 3/4 scored lower

6 0
1 year ago
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
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