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Natali [406]
3 years ago
15

In average, each person in the industrialized world is responsible for the emission of 10,000 kg of carbon dioxide (CO2)(CO2) ev

ery year. This includes CO2CO2CO_2 that you generate directly, by burning fossil fuels to operate your car or your furnace, as well as CO2CO2CO_2 generated on your behalf by electric generating stations and manufacturing plants. CO2CO2CO_2 is a greenhouse gas that contributes to global warming. If you were to store your yearly emissions in a cube at STP, how long would each edge of the cube be?
Chemistry
1 answer:
Pani-rosa [81]3 years ago
7 0

Answer:

The length of the cubical container will be 17.206 m.

Explanation:

Amount of carbon dioxide gas generated in year by person = 10,000 kg

1 kg = 1000 g

10,000 kg = 10,000 × 1000 g = 10,000,000 g

Moles of carbon dioxide = \frac{10,000,000 g}{44 g/mol}=227,272.72 mol

Volume of carbon dioxide gas at STP= V

STP conditions = P = 1 atm , T = 273 K

Using Ideal gas equation ;

PV=nRT

V=\frac{nRT}{P}=\frac{227,272.72mol\times 0.0821 atm L/mol K\times 273 K}{1 atm}

V=5,093,931.82 L

1 L = 0.001 m^3

V=5,093,931.82 L=5,093,931.82 \times 0.001 m^3=5,093.93182 m^3

Let the side of the cube = a

Volume of the cube = a^3

V=5,093.93182 m^3

a^3=5,093.93182 m^3

a=\sqrt{5,093.93182 m^3}=17.206 m

The length of the cubical container will be 17.206 m.

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A balloon contains 11.1 g of nitrogen monoxide gas (NO). how many molecules are in the balloon?
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<h3> calculation</h3>

calculate the number of moles of NO

moles = mass/molar mass

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by use of Avogadro's constant that is

                                     1 mole= 6.02 x10^23  molecules

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147 n = 847.56
divide bot
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