How can you write 8⁴•7⁴ as a single power?

egoroff_w [7]

Answer:

i believe it would be d square root of 17

6 0

3 years ago

Which shapes can be made from a planar cross section of a triangular pyramid? More than one can be correct: trapezoid, pentagon,

Jlenok [28]

Answer:

Triangle in isosceles, scalene or equilateral forms and

quadrilateral in trapezoid, rectangle or square forms

Step-by-step explanation:

Refer to pictures attached

Shapes can be formed are:

Trapezoid,

when perpendicular to base

Rectangle or square,

when angle cross section to base

Isosceles triangle,

when base is isosceles triangle and parallel cross section to base,

or angle cross section

Scalene triangle,

when base is scalene triangle and parallel cross section to base,

or angle cross section

Equilateral triangle,

when base is equilateral triangle and parallel cross section to base,

or angle cross section

7 0

3 years ago

How many 12 ounces cans of soda equal 108 ounces?

Savatey [412]

Answer:

9 Sodas

Step-by-step explanation:

Because 12 times 9 equals 108

6 0

3 years ago

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David and Lacey are 2000 feet apart on a coastline. They each look at the same boat in the water. The angle between the coastlin

Ulleksa [173]

By using the given distances and directions, we have;

Part A: 1083.5 feet

Part B: 1921.37 feet

Part C: 58.05°

<h3>How can the distances and directions be calculated?</h3>

The distance between David and Lacey = 2000 feet

David's angle to the boat = 70°

Lacey's angle to the boat = 32°

Part A

The distance of the boat from David is found as follows;

Imaginary lines drawn from the boat to David and then to Lacey form a triangle.

In the triangle, let A = 70°

B = 32°

Therefore by the sum of angles in a triangle, we have;

C = 180° - (70° + 32°) = 78°

By using sine rule we have;

$\frac{a}{sin(A)} = \frac{b}{sin( B )} = \frac{c}{sin(C)}$

David's distance from the boat, b, is therefore;

$\frac{b}{sin( 32 )} = \frac{2000}{sin(78)}$

The angle subtended by the coastline, C, is therefore;

$b = \frac{2000}{sin(78)} \times sin( 32 ) = 1083.5$

David's distance from the boat is 1083.5 feet

Part B

The distance between the boat and Lacey is found as follows;

$\mathbf{ \frac{a}{sin( 70)} }= \frac{2000}{sin(78)}$

$a = \frac{2000}{sin(78)} \times sin( 70 ) = 1921.37$

Lacey's distance from the boat is 1921.37 feet

Part C

When b = 1200 feet, we have;

Finding the vertical distance of the boat from the coastline, we have;

1083.5 × sin(70) = 1018.17

We have;

$\frac{1200}{sin(90)} = \frac{1018.17}{sin( B' )}$

${sin( B' )} = \frac{sin(90)}{1200} \times 1018.17$

The angle between the coastline and his view to the boat, B', is therefore;

B' = arcsine (1018.17÷1200) = 58.05°

Learn more about sine rule here:

brainly.com/question/4372174

#SPJ1

4 0

2 years ago

Find all values of m so that the function y = emx is a solution of the given differential equation. (enter your answers as a com

astraxan [27]

$y=e^{mx}\implies y'=me^{mx}$

$y'+6y=0\iff me^{mx}+6e^{mx}=(m+6)e^{mx}=0\implies m=-6$

So one solution to the ODE is $y=e^{-6x}$ .

3 0

3 years ago

Read 2 more answers