All categories

3 years ago

How do you balance this equation?

Chemistry

1 answer:

anyanavicka [17]3 years ago

5 0

Answer:

HC₂H₃O₂ + NaHCO₃ —> NaC₂H₃O₂ + CO₂ + H₂O

The coefficients are: 1, 1, 1, 1, 1

Explanation:

_HC₂H₃O₂ + _NaHCO₃ —> _NaC₂H₃O₂ + _CO₂ + _H₂O

To balance an equation, we simply do a head count of the individual elements and ensure they are balanced on both side.

For the above equation, we shall balance it as :

HC₂H₃O₂ + NaHCO₃ —> NaC₂H₃O₂ + CO₂ + H₂O

Reactant:

H = 5

C = 3

O = 5

Na = 1

Product:

H = 5

C = 3

O = 5

Na = 1

From the above, we can see that each element is the same on both side of the equation. Thus the equation is already balanced

HC₂H₃O₂ + NaHCO₃ —> NaC₂H₃O₂ + CO₂ + H₂O

The coefficients are: 1, 1, 1, 1, 1

You might be interested in

18.The average or small size stars become a _________ at the end of their life cycle.

wel

The answer is B, Neutron star

5 0

3 years ago

What is the molarity of a 750 milliliters solution containing 54.0 grams of KBr (help me please)

ololo11 [35]

<u>Answer:</u> The molarity of KBr solution is 0.605 M

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L.

The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}$ .....(1)

Given values:

Given mass of KBr = 54.0 g

Molar mass of KBr = 119 g/mol

Volume of the solution = 750 mL

Putting values in equation 1, we get:

$\text{Molarity of solution}=\frac{54.0\times 1000}{119\times 750}\\\\\text{Molarity of solution}=0.605M$

Hence, the molarity of KBr solution is 0.605 M

7 0

3 years ago

Orbital structure of sodium?

algol13

Answer:

na.

sodium

11( 2,81,)

pls Mark me as brainlest

5 0

3 years ago

What are the products in the following chemical reaction?

hodyreva [135]

The products are on the right side of the chemical equation, while the reactants are on the left side of the chemical equation.

Therefore if we have:

methane + oxygen → carbon dioxide + water

Then the reactants are methane + oxygen

The products are: A) Carbon dioxide + Water

4 0

3 years ago

A sample of helium gas has a volume of 1.50 L at 159 K and 5.00 atm. When the gas is compressed to 0.200 L at 50.0 atm, the temp

Brums [2.3K]

Answer:

ghdtgfgrdvreeeegrwwggegteefewqrwefrwerrftrtdsfgyuytfgererdf

Explanation:

The given data is as follows.

$V_{1}$ = 1.50 L, $T_{1}$ = 159 K,

$P_{1}$ = 5.00 atm, $V_{2}$ = 0.2 L,

$T_{2}$ = ?, $P_{2}$ = 50.0 atm

And, according to ideal gas equation,

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Hence, putting the given values into the above formula to calculate the value of final temperature as follows.

$\frac{5.0 atm \times 1.50 L}{159 K} = \frac{5 atm \times 0.2 L}{T_{2}}$

$T_{2}$ = 21.27 K

Thus, we can conclude that the final temperature is 21.27 K .

5 0

3 years ago