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Morgarella [4.7K]
3 years ago
8

GRAHAM CORPORATION

Mathematics
1 answer:
astra-53 [7]3 years ago
5 0

Answer:

<h2>Net proceed= s-0.98nd-11</h2>

Step-by-step explanation:

Given that the shares cost $d

n shares will be =$dn

paid 2% commission to her broker= (2/100)*nd= 0.02nd

sold the share for $s

paid a fee of $11

Her net proceeds algebraically will be

Net proceed= s-nd-11-0.02nd

collect like terms

Net proceed= s-(nd-0.02nd)-11

Net proceed= s-0.98nd-11

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we are given

\frac{1}{2} (\frac{3}{2} x+6x+1)-3x

step-1: Simplify expression inside parenthesis

we will combine like terms

so, firstly we will take common denominator

\frac{1}{2} (\frac{3}{2} x+\frac{2*6}{1*2}x+1)-3x

\frac{1}{2} (\frac{3x+12x}{2} +1)-3x

\frac{1}{2} (\frac{15x}{2} +1)-3x

step-2: Distribute 1/2 inside

=\frac{1}{2} *\frac{15x}{2} +1*\frac{1}{2}-3x

=\frac{15x}{4} +\frac{1}{2} -3x

step-3: Combine like terms

=\frac{15x}{4}+3x +\frac{1}{2}

We can find common denominator

=\frac{15x}{4}-\frac{4*3x}{4*1} +\frac{1}{2}

=\frac{15x}{4}-\frac{12x}{4} +\frac{1}{2}

=\frac{15x-12x}{4} +\frac{1}{2}

=\frac{3x}{4} +\frac{1}{2}

we can also write it as in mixed form

=\frac{3}{4}x +\frac{1}{2}

so, we will get

\frac{1}{2} (\frac{3}{2} x+6x+1)-3x=\frac{3}{4}x +\frac{1}{2}

option-C.............Answer

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4 years ago
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