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3 years ago

GRAHAM CORPORATION

Mathematics

1 answer:

astra-53 [7]3 years ago

5 0

Answer:

<h2>Net proceed= s-0.98nd-11</h2>

Step-by-step explanation:

Given that the shares cost $d

n shares will be =$dn

paid 2% commission to her broker= (2/100)*nd= 0.02nd

sold the share for $s

paid a fee of $11

Her net proceeds algebraically will be

Net proceed= s-nd-11-0.02nd

collect like terms

Net proceed= s-(nd-0.02nd)-11

Net proceed= s-0.98nd-11

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Can someone help me please, explain in your own words. I'll give brainliest to the best and correct answer. Thank you (:

Elanso [62]

A) To factor a quadratic equation, standard form is the better form to use because it is easier to pull out a common factor from.

b) To graph a parabola, it is better to use vertex form so that you will know what point to graph as the vertex of the parabola.

c) To identify the vertex, maximum and minimum, it is better to use vertex form because the vertex form will give the values of the coordinates for the vertex. Then, you can use the equation to find the mininmum or maximum. If the graph is negative, it will have a maximum because it points downward infinitely. If the equation is positive, the graph will have a minimum because the graph points upward infinitely.

d) Standard form is easier to use when trying to solve using the quadratic formula because it is easier to see what the coeffiecnts and constants are to plug in for a b and c.

6 0

3 years ago

Which equation is y = –6x^2 + 3x + 2 rewritten in vertex form? y = negative 6 (x minus 1) squared + 8 y = negative 6 (x + one-fo

mart [117]

Answer:

$y = -6(x - \frac{1}{2})^2 -\frac{7}{2}$

Step-by-step explanation:

Given:

$y = -6x^2 + 3x + 2$

Required

Rewrite in vertex form

The vertex form of an equation is in form of: $y = a(x - h)^2+ k$

Solving: $y = -6x^2 + 3x + 2$

Subtract 2 from both sides

$y - 2 = -6x^2 + 3x + 2 - 2$

$y - 2 = -6x^2 + 3x$

Factorize expression on the right hand side by dividing through by the coefficient of x²

$y - 2 = -6(x^2 + \frac{3x}{-6})$

$y - 2 = -6(x^2 - \frac{3x}{6})$

$y - 2 = -6(x^2 - \frac{x}{2})$

Get a perfect square of coefficient of x; then add to both sides

------------------------------------------------------------------------------------

<em>Rough work</em>

The coefficient of x is $\frac{-1}{2}$

It's square is $(\frac{-1}{2})^2 = \frac{1}{4}$

Adding inside the bracket of $-6(x^2 - \frac{x}{2})$ to give: $-6(x^2 - \frac{x}{2} + \frac{1}{4})$

To balance the equation, the same expression must be added to the other side of the equation;

Equivalent expression is: $-6(\frac{1}{4})$

------------------------------------------------------------------------------------

The expression becomes

$y - 2 -6(\frac{1}{4})= -6(x^2 - \frac{x}{2} + \frac{1}{4})$

$y - 2 -\frac{6}{4}= -6(x^2 - \frac{x}{2} + \frac{1}{4})$

$y - 2 -\frac{3}{2}= -6(x^2 - \frac{x}{2} + \frac{1}{4})$

Factorize the expression on the right hand side

$y - 2 -\frac{3}{2}= -6(x - \frac{1}{2})^2$

$y - (2 +\frac{3}{2})= -6(x - \frac{1}{2})^2$

$y - (\frac{4+3}{2})= -6(x - \frac{1}{2})^2$

$y - (\frac{7}{2})= -6(x - \frac{1}{2})^2$

$y +\frac{7}{2} = -6(x - \frac{1}{2})^2$

Make y the subject of formula

$y = -6(x - \frac{1}{2})^2 -\frac{7}{2}$

<em>Solved</em>

7 0

4 years ago

Read 2 more answers

Im gon be posting a lot so helppp

almond37 [142]

12/3 is rational

DescriptionIn mathematics, a rational number is a number that can be expressed as the quotient or fraction

6 0

3 years ago

Read 2 more answers

Whats up you mofos good morning

Paul [167]

yap mofos morning good

6 0

3 years ago

Which expression is equivalent to 16x4 – 64? and explain the answer plzz

GuDViN [60]

Answer:

4(4x1-16)

Hope this helps

Have a good day :)

PS I disibuted 4 to 4x1 to get 16 and 4 to -16 to get -64

Step-by-step explanation:

3 0

3 years ago