N = ?
T = 449 K
V = 58.35 L
P =2.97
R = 0.082
Use the clapeyron equation:
P x V = n x R x T
2.97 x 58.35 = n x 0.082 x 449
173.2995 = n x 36.818
n = 173.2995 / 36.818
n = 4.70 moles
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Answer:
Become familiar with the chemicals to be used, including exposure or spill hazards.
Locate the spill kits and understand how they are used.
Explanation:
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Answer: 600°C
Explanation:
This reaction is explained by Charles' law as the pressure is constant.
From the question, we obtained:
V1 = 67mL
T1 = 18°C = 18 +273 = 291K
V2 = 3V1 ( Vol is tripled) = 3x67 = 201mL
T2 =?
Applying the Charles' law,
V1 /T1 = V2 /T2
67/291 = 201 / T2
Cross multiply to express in linear form.
67xT2 = 291x201
Divide both side by 67, we have:
T2 = (291x201) /67
T2 = 873K
Converting to Celsius temperature, we have
T°C = K — 273
T°C = 873 — 273 = 600°C
Given what we know, we can confirm that an example is a situation given that corroborates the information shown, while a non-example is one that does not fall in line with the information provided.
<h3>What are examples of the situations given?</h3>
- A number that is a multiple of 10 is 40, since 10 times 4 equals 40.
- In order to get a product of 10, we can multiply two and five.
- To result in a quotient of 10, we can divide one hundred by ten.
<h3>What are non-examples of the situations given?</h3>
- one non-example of a multiple of 10 would be to multiply three and seven.
- A non-example of a product of 10 is to multiply the number fifty by twenty-five.
- To result in a non-example for a quotient of 10, we can divide the number fifteen by three.
Therefore, given the definition of an example as a situation given that corroborates the information shown, while a non-example is one that does not fall in line with the information provided, we can confirm that the ones listed above are correct.
To learn more about examples visit:
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