32 models need to make model of 3200.
Given that a 1 model contain 100.
Two series of numbers, usually empirical data, that are proportional or proportional if their respective elements are in constant proportion, called the scaling factor or the rate constant.
One model has 100 elements.
Now, we have to find how many model contains 3200 elements.
So, 1 model=100 elements
n model =3200 elements
We will write this in proportion as
1/n=100/3200
Applying the cross multiply, we get
3200×1=n×100
Divide both sides with 100, we get
3200/100=100n/100
3200/100=n
32=n
Hence, the 32 models contain 3200 elements when one contain 100 elements.
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Answer:
Check explanations
Step-by-step explanation:
For all real numbers a,b, and c, the distributive property states that:

For Part A, we have

Or

For Part B, we have
-4(3x-10)+5(2-6x)=-4*3x--4*10+5*2-5*6x
This simplifies to:
-4(3x-10)+5(2-6x)=-12x+40+10-30x
-4(3x-10)+5(2-6x)=-12x-30x+40+10
-4(3x-10)+5(2-6x)=-42x+50
For the C part, we have:



For Part D, we have:

We simplify to get:

Simplify further to get:

13.42 is how long the wire is to the nearest hundredth of a foot
Answer:
-52
Step-by-step explanation:
plug 2 into u(x) which is equal to
2(5) + 1= 5
plug 5 into w(x) which is equal to
-2(5^2) - 2
-2(25) - 2
-50 - 2 = -52