1.6456 x 10^3 (ten to the third power)
3. 4 g of a nonelectrolyte dissolved in 78. 3 g of water produces a solution. The molar mass of the solute will be 17.94.
<h3>
What is molar mass?</h3>
Molar mass of a substance is its mass in grams in per mole of a solution.
Freezing point: Freezing point of a substance is a temperature at which a liquid starts to solidify.
Depression in the freezing point can be calculated
[Depression in freezing point of pure solvent—Freezing point of solution] =[(0) - (-4.5)] °C =4.5 °C
molar mass = Number of moles of solute m / Mass of solvent in Kg
3.4g / M x 1/ 0.0783 kg = 43.42
Substitute AT by 4.5°C , Kr by 1.86 °C/m, and m by 43.42 m in equation (1) as follows:
1.86 x 43.42 / 4.5 = 17.94
Therefore, molar mass of solute to be 17.94.
To learn more about molar mass, refer to the link:
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Molar mass sucrose :
C12H22O11 = 342.29 g/mol
number of moles <span>of the solute :
</span>
n = mass solute / molar mass
n = 17.1 / 342.29
n = 0.05 moles
Volume in liters :
250 mL / 1000 = 0.25 L
therefore :
Molarity = moles of solute / volume
Molarity = 0.05 / 0.25 => 0.2 mol/L
Answer:
Mole Fraction = 0.059
Explanation:
To find the mole fraction, you need to (1) convert grams H₂SO₄ and H₂O to moles (via molar mass) and then (2) calculate the mole fraction.
(Step 1)
Molar Mass (H₂SO₄): 98 g/mol
34 grams H₂SO₄ 1 mole
-------------------------- x ------------------- = 0.347 moles H₂SO₄
98 grams
Molar Mass (H₂O): 18 g/mol
100 grams H₂O 1 mole
------------------------- x -------------------- = 5.56 moles H₂O
18 grams
(Step 2)
moles solute
Mole Fraction = -------------------------------------------------
moles solute + moles solvent
0.347 moles H₂SO₄
Mole Fraction = -----------------------------------------------------------
0.347 moles H₂SO₄ + 5.56 moles H₂O
Mole Fraction = 0.059
