Mass atomic of Ne=20.18 u
Therefore:
molar mass=20.18 g/1 mol
1 mole=6.022*10²³ particles (atoms or molecules)
Then: 6.022*10²³ atoms are contained in 20.18g
Now, We can solve this problem by the three rule.
6.022*10²³ atoms-------------------20.18 g
x------------------------------------------32 g
x=(6.022*10²³ atoms * 32 g)/20.18 g=9.55*10²³ atoms.
Answer: 9.55*10²³ Ne atoms are contained in 32 g of the element.
Answer:
this was the last of .the last 555543 years of 55my in
Explanation:
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Answer:
C.)One electron in each p orbital
Explanation:
In a P-sublevel with 3 electrons, they should be arranged with one electron going into each p-orbitals.
This is in accordance with the Hund's rule of maximum multiplicity.
The rule states that "electrons go into degenerate orbitals or sub-levels(p,d and f) singly before paring up".
Since the p-orbital is 3-fold degenerate with a capacity to accommodate a maximum number of 6 electrons, given 3 electrons, they will follow the Hund's rule in order to fill the orbitals.
So one electron will go in each p - orbitals easily.
It’s C.valley formed from water erosion
Answer: 700 has one significant figure which is 7.
Explanation: These are some rules for significant figures
•All non-zero digits are significant: 1,2,3,4,5,6,7,8,9
•Zero between non-zero digits are significant: They are three significant figures in 203.
•Leading zeros are not significant: There are two significant figures in 0.56.
•Trailing zero to the right of decimal are significant. There are four significant figures in 62.00
•Trailing zeros in a whole number with the decimal shown are significant: This makes "700." three significant figures.
•Trailing zeros in a whole number with no decimal shown are not significant: This makes 700 one significant figure.
