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nadezda [96]
3 years ago
15

what is the percent by mass of NaHCO3 in a solution containing 20.0 g of NaHCO3 dissolved in 600.0 ml of water

Chemistry
1 answer:
Ne4ueva [31]3 years ago
7 0
%(NaHCO3)= ((mass NaHCO3)/(mass NaHCO3 + mass water))*100%

m=Volume*Density
Density of water =1 g/ml
m(water) = Volume(water)*Density(water) = 600.0 ml * 1g/ml=600g water

%(NaHCO3)= ((20.0 g)/(20.0 g + 600 g))*100%=0.0323*100%=32.3%
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Shkiper50 [21]

Answer:

The stronger conjugate base will be the weaker acid; i.e., the acid with the smaller Ka-value.

Explanation:

Given conjugate base CN⁻ => weak acid => HCN =>  Ka =4.9 x 10⁻¹⁰

Given conjugate base OCN⁻ => weak acid=> HOCN => Ka = 3.5 x 10⁻⁴

Ka(HCN) << Ka(HOCN) => CN⁻ is a much stronger conjugate base than OCN⁻

6 0
2 years ago
The cavity within a copper [β = 51 × 10-6 (C°)-1] sphere has a volume of 1.220 × 10-3 m3. Into this cavity is placed 1.100 × 10-
juin [17]

Answer:

Δ should be 0.1009

Explanation:

The change in the units volume when temperature change can be expressed as:

∆v = v0Δ

with v0 = the initial volume

with = the volumetric temperature expansion coefficient

with Δ  = the change of temperature.

To calculate the final volume vf we'll get:

v = v0 + ∆ = v0(1 + Δ)

The liquid just begins to spill out if v(benzene) = :

v()(1 + Δ) = = v() (1 + Δ)

(v(cavity)-v(benzene))/(((benzene) -(copper)) = Δ

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5 0
3 years ago
Calculate the moles of SO2 that contains 3.8 moles of O atoms
Olegator [25]
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Explanation:

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2) Then you can state the proportion between the number of moles of SO₂ and O to find how many moles of SO₂:contains 3.8 moles of O.


   1 mol SO₂                         x

-------------------- =   --------------------------

    2 moles O              3.8  moles O


3) Now, you can clear x:

x = 3.8 moles O × 1 mol SO₂ / 2 moles O.

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5 0
3 years ago
3. Hexane (C6H-2) is combusted in oxygen
Lapatulllka [165]

Answer:

                   a)  9.5 moles of Oxygen

                    b)  1.029 × 10²⁵ Molecules

Explanation:

                    The balance chemical equation for said reaction is as follow:

                               2 C₆H₁₄ + 19 O₂   →  12 CO₂ + 14 H₂O

A)

According to equation,

              2 moles of C₆H₁₄ are reacted with  =  19 moles of O₂

So,

                   1 moles of C₆H₁₄ will react with  =  X moles of O₂

Solving for X,

                      X  =  19 moles × 1 mole / 2 moles

                       X  =  9.5 moles of Oxygen

B)

For this part first calculate moles of hexane as;

                             Moles  =  Mass / M.Mass

                             Moles  =  245.5 g / 86.18 g/mol

                             Moles  =  2.84 mole of Hexane

Secondly, find the number of moles of CO₂ as,

According to equation,

              2 moles of C₆H₁₄ produced  =  12 moles of CO₂

So,

                   2.84 moles of C₆H₁₄ will produce  =  X moles of CO₂

Solving for X,

                      X  =  12 moles × 2.84 mole / 2 moles

                       X  =  17.09 moles of CO₂

Lastly, calculate the number of molecules of CO₂ as,

Number of Molecules  =  Moles × 6.022 × 10²³ molecules/mole

Number of Molecules  =  17.09 moles × 6.022 × 10²³ molecules/mole

Number of Molecules  =  1.029 × 10²⁵ Molecules

4 0
2 years ago
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/watch?v=DLzxrzFCyOs

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