Answer:
Area of this parallelogram A = base x height = 11 x 6 = 66 (cm2)
Hope this helps!
:)
<h3>
Answer: C) 0</h3>
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Explanation:
If points F and E are the midpoints of segment VU and segment ST respectively, then segment FE is the midsegment of the trapezoid. The midsegment is parallel to the bases, and the midsegment's length is found by adding up the bases VS and UT, then dividing by 2.
(VS + UT)/2 = FE
(29 + x+17)/2 = 23 ... plug in given info; isolate x
(x+46)/2 = 23
x+46 = 23*2 ... multiply both sides by 2
x+46 = 46
x = 46-46 ... subtract 46 from both sides
<h3>
x = 0</h3>
Answer:
x = pp12 or 12 pp
Step-by-step explanation:
Just to note that pp means p square
In order to do this, one side of the rectangle will be x+2, and the other will just be x. The x would be representing the width since the length is the width (x) plus two feet (+2). Next, you have to make an equation. So, since it all has to use 16 feet of fencing, you would set the two sides to be added to equal 16. So, it would be: 16=x+2+x. Then, you reduce that, so it would be: 16=2x+2. After that you just solve for x (which means that you want x by itself on one side of the = ). So, you would subtract 2 from both sides. Since 2-2=0, that would make the "+2" go away; since 16-2=14, that would replace the 16. So, your new equation is: 14=2x. After that you just divide both sides by 2 because 2 divided by 2=0. 14/2=7. So, you would end up getting: 7=x as your final answer.
Now, you just put 7 where x was in the sides. So 2x (which was the length) trims into: 2 times 7, which =14 and the x (which was the width) we already figured out was 7. This, the width would be 7, while the length would be 14.
