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Serga [27]
3 years ago
15

When a candle burns, which forms of energy does the chemical energy in the candle change to? A. light and sound B. heat and soun

d C. light and heat D. electric and light
Physics
2 answers:
Nutka1998 [239]3 years ago
8 0

Answer:

C. light and heat

Explanation:

When the candle is burnt, the chemical energy is converted to light and heat.

Light is easily visible. Heat is dependent on the size of the candle. If a small candle is burnt heat will not be much and can only be felt if one is very close to its flame.

Sound waves and electrical energies are not created while a candle burns.

Ratling [72]3 years ago
3 0

Answer:

When a candle burns, the chemical energy in the candle changes to light energy and heat energy.<em> (C)</em>

Explanation:

Did you ever light a candle and have sound or electricity come out of it ? ?

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A(n) 1946 kg car travels at a speed of 10 m/s . What is its kinetic energy ? Answer in units of J.
erica [24]

Answer:

KE=97300J

Explanation:

KE=1/2mv^2

KE=1/2(1946)(10)^2

KE=97300J

4 0
3 years ago
Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 100 kg ball tr
sashaice [31]

Okay, first off, the formula for Kinetic Energy is:

<em>KE = 1/2(m)(v)^2</em>

<em>m = mass</em>

<em>v = velcoity (m/s)</em>


Using this formula, we can then calculate the kinetic energy in each scenario:

1) KE = 1/2(100)(5)^2 = 1,250 J

2) KE = 1/2(1000)(5)^2 = 12,500 J

3) KE = 1/2(10)(5)^2 = 125 J

4) KE = 1/2(100)(5)^2 = 1,250 J

4 0
3 years ago
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The position of a 50 g oscillating mass is given by x(t)=(2.0cm)cos(10t−π/4), where t is in s. If necessary, round your answers
Leona [35]
For the answer to the question above, this is the maximum displacement, the spring has only elastic potential energy.
spring is constant @ 5 N/m
maximum displacement = 2 cm = 0.02 m
elastic potential energy = 1/2 kx²
= 0.5 x 5 x 0.02²
So the answer would be
= 0.001 Joules
5 0
3 years ago
Suppose the kicker launches the ball at 60∘ instead of 30∘. Assuming that the goal is 4.55 m high and 40 m away, what minimum in
Nikitich [7]

Answer:22 m/s

Explanation:

Given

launch angle \theta =60^{\circ}

height of goal h=4.55\ m

and horizontal distance x=40\ m

Suppose initial speed is u

Trajectory of a Projectile is given by

y=x\tan \theta -\frac{1}{2}\frac{gx^2}{u^2\cos ^2\theta }

substituting the values we get

4.55=40\tan (60)-0.5\times \frac{9.8\times (40)^2}{u^2\cdot \cos ^260 }

4.55=69.28-0.5\times \frac{15,680}{u^2\cdot 0.25}

\frac{31,360}{u^2}=69.28-4.55

\frac{31,360}{64.73}=u^2

u^2=484.47

u=22.01\ m/s

So, initial launch speed is 22\ m/s

4 0
3 years ago
Norma kicks a soccer ball with an initial velocity of 10.0 meters per second at an angle of 30.0°.
amm1812

Answer: 30

Explanation:

7 0
2 years ago
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