When a candle burns, which forms of energy does the chemical energy in the candle change to? A. light and sound B. heat and soun
2 answers:
You might be interested in
hi brainly user! ૮₍ ˃ ⤙ ˂ ₎ა
⊱┈────────────────────────┈⊰
Considering that the pulley is fixed, the force applied should be equal to the weight of the object - of 400N.
Pulleys or pulleys are mechanical tools used to assist in the movement of objects and bodies. There are two types of pulleys: fixed and movable. While the fixed pulley changes the direction of force, the moving pulley helps to decrease the force needed to move the object or body in question.
As the statement only tells us a pulley, we must consider that it is fixed, <u>because generally when it is mobile, this information is highlighted in the question</u>.
In this way, a fixed pulley only changes the direction of the applied force. Thus, the force must have the same magnitude as the weight of the object to be moved. If the bucket weighs 400N, the force applied to the pulley must be 400N.
<u>Therefore, having a fixed pulley, the force applied must be equal to the weight of the object, and will be 400N.</u>
The given vectors quantities can be described by their properties of both
magnitude and direction.
- a. The drawing of the vector extending from point (0, 0) to (190, 0) on the coordinate plane is attached.
- b. The velocity vector extending from (0, 0) to (108.76, 50.714) on the coordinate plane is attached.
- c. The displacement vector extending from (0, 0) to (30·√2, 30·√2) is attached.
Reasons:
a. The magnitude of the vector = 190 N
The direction in which the vector acts = East
Therefore, in vector form, we have;
= 190 × cos(0)·i + 190 × sin(0)·j = 190·i
The vector can be represented by an horizontal line, 190 units long
Coordinate points on the vector = (0, 0) and (190, 0)
The drawing of the vector with the above points using MS Excel is attached.
b. Magnitude of the velocity vector = 120 km/hr. 25° North of east
Solution;
The vector form of the velocity is; = 120 × cos(25)·i + 120×sin(25)·j, which gives;
= 120 × cos(25)·i + 120×sin(25)·j ≈ 108.76·i + 50.714·j
≈ 108.76·i + 50.714·j
Therefore, points that define the vector are; (0, 0) and (108.76, 50.714)
The drawing of the vector is attached
c. The magnitude of the vector = 60 m
The direction of the vector is southwest = West 45° south
The vector form of the displacement is = 60 × cos(45°)·i + 60 × sin(45°)·j
Which gives;
= 30·√2·i + 30·√2·j
Points on the vector are therefore; (0, 0), and (30·√2, 30·√2)
The drawing of the vector is attached
Learn more about vectors here:
