When a candle burns, which forms of energy does the chemical energy in the candle change to? A. light and sound B. heat and soun
2 answers:
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Answer:
The velocity of the first block is 1.15m/s while of the second block 2.56m/s.
Explanation:
Momentum is only conserved in an isolated system, and because this problem requires us to find the value of the two variables, we need two equations; therefore, to conserved momentum the energy must be released in to the system only after the collision has occurred.
Therefore, from conservation of momentum
and from conservation of energy
Thus, we have two equations and two unknowns
which has solutions
and
Since the blocks cannot pass through each other, the 0.5kg block cannot have (moves to the left) while the 0.4 kg block has
(moves to the right); therefore, we take the first solution for the velocities:
.
Thus , the velocity of the first block is 1.15m/s while of the second block 2.56m/s.
(a) 10 GHz is the frequency of microwave radiation.
(b) 0.167 ms is required by the microwave to travel between two mountains.
Answer:
Explanation:
(a). 1 MHz is the frequency of microwave radiation.
(b) 0.167 ms is required by the microwave to travel between two mountains.
Answer:
Explanation:
a. Frequency is the measure of number of times a same thing will be repeated in a given time interval for a given time. And wavelength is the measure of distance between two successive crests or troughs. So wavelength and frequency are inversely proportional to each other. And velocity of light is the proportionality constant.
So frequency of microwave radiation = Speed of light/Wavelength of radiation
Frequency =
Frequency =
So 10 GHz is the frequency of microwave radiation.
b). As microwave is a part of light waves, so it will be experiencing the speed of light.
As the speed is 3* m/s and the distance between the two mountains is given as 50 km, then time can be calculated as
Time = Distance/Velocity
Time =
So time = 0.167 ms.
Thus, 0.167 ms is required by the microwave to travel between two mountains.