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aalyn [17]
2 years ago
6

List the three products of radioactive decay from the most penetrating to the least penetrating

Physics
1 answer:
Helen [10]2 years ago
8 0
<span>1.Gamma   
2.Beta 
3.Alpha

</span>
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How much power will it take to move a 10 kg mass at an acceleration of 2 m/s² a distance of 10 meters in 5 seconds?
DedPeter [7]

Answer:

100 Watts

Explanation:

<u>These equations are needed to work out the answer:</u>

  • power= work done/ time taken
  • work done= force* distance
  • force= mass* acceleration

force: 10 kg* 2m/s= 20

work done: 20* 10m=200

power: 200/2=100

7 0
2 years ago
A point charge q is located at the center of a spherical shell of radius a that has a charge −q uniformly distributed on its sur
muminat

Answer:

a) E = 0

b) E =  \dfrac{k_e \cdot q}{ r^2 }

Explanation:

The electric field for all points outside the spherical shell is given as follows;

a) \phi_E = \oint E \cdot  dA =  \dfrac{\Sigma q_{enclosed}}{\varepsilon _{0}}

From which we have;

E \cdot  A =  \dfrac{{\Sigma Q}}{\varepsilon _{0}} = \dfrac{+q + (-q)}{\varepsilon _{0}}  = \dfrac{0}{\varepsilon _{0}} = 0

E = 0/A = 0

E = 0

b) \phi_E = \oint E \cdot  dA =  \dfrac{\Sigma q_{enclosed}}{\varepsilon _{0}}

E \cdot  A  = \dfrac{+q }{\varepsilon _{0}}

E  = \dfrac{+q }{\varepsilon _{0} \cdot A} = \dfrac{+q }{\varepsilon _{0} \cdot 4 \cdot \pi \cdot r^2}

By Gauss theorem, we have;

E\oint dS =  \dfrac{q}{\varepsilon _{0}}

Therefore, we get;

E \cdot (4 \cdot \pi \cdot r^2) =  \dfrac{q}{\varepsilon _{0}}

The electrical field outside the spherical shell

E =  \dfrac{q}{\varepsilon _{0} \cdot (4 \cdot \pi \cdot r^2) }= \dfrac{q}{4 \cdot \pi \cdot \varepsilon _{0} \cdot r^2 }=  \dfrac{q}{(4 \cdot \pi \cdot \varepsilon _{0} )\cdot r^2 }

k_e=  \dfrac{1}{(4 \cdot \pi \cdot \varepsilon _{0} ) }

Therefore, we have;

E =  \dfrac{k_e \cdot q}{ r^2 }

5 0
2 years ago
9. True or False: Sawmills and gristmills are machines that do not need
gizmo_the_mogwai [7]

Answer:

true can i get brainliest :)

Explanation:

4 0
3 years ago
What is the dimensional formula of pressure ??​
Igoryamba

Answer:

pressure is equal to the net amount of force acting per unit area. Dimensional Formulae of force is M1L1T-2 and of area is L2. Therefore Pressure's dimension can be obtained by calculating Force by Area. Dimensional formula of pressure difference is M1L-1T-2.

3 0
2 years ago
Relationship between frequency, amplitude, wavelength and energy in a transverse wave.
liq [111]
In a transverse wave:
- Oscillations are perpendicular to the direction of energy travelling
- Frequency is the amount of complete waves passing a certain point in one second (measured in hertz, Hz)
- Wavelength is the distance from any point on one wave to the same point on the following wave
- The amplitude is the maximum displacement of the particles from their average position (and be measured from the horizontal mid-point of the wave to either the peak or trough)

There isn't always a defined relationship between these features. However, frequency × wavelength = velocity of the wave.
3 0
3 years ago
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