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Orlov [11]
3 years ago
7

An important consideration in materials physics is the number of defects that are unavoidable due to statistical considerations.

Defects influence structural, electronic and optical properties. The equilibrium statistical physics of defects in a material can be modeled as a collection of N two-state systems. Every atomic site can be either, (a) occupied with an atom, in which case its energy is zero, or (b) occupied by a defect, in which case its energy is e. The formation energy (€) is the energy needed to remove an atom from the regular lattice position to an interstitial position, from which it diffuses out of the crystal
(a) Determine the partition function for this system, in terms of N, E, and T.
(b) What is the Helmholtz free energy (F) and the internal energy (U) for a sample of N atoms?
(c) What is the average number of defects, in terms of N, E, and T?
(d) Assume the formation energy is 1 eV. If you have a collection of spherical copper nanocrystals with a radius of 50 nm at room temperature, what is the minimum number of nanocrystals that you would need in a sample before you could expect (on average) that only one of them would have a single defect and the others would be defect free?

Physics
1 answer:
goblinko [34]3 years ago
8 0

Answer:

Explanation:

find attached the solution

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A bungee jumper has a mass of 60kg and uses a 25m long bungee cord (unstretched length) with an elastic coefficient of 800N/m. a
KonstantinChe [14]

Answer:

a ) 2.68 m / s

b )  1.47 m

Explanation:

The jumper will go down with acceleration as long as net force on it becomes zero . Net force of (mg - kx ) will act on it  where kx is the restoring force acting in upward direction.

At the time of equilibrium

mg - kx = 0

x = mg / k

= (60 x 9.8 ) / 800

= 0.735 m

At this moment , let its velocity be equal to V

Applying conservation of energy

kinetic energy of jumper + elastic energy of cord = loss of potential energy of the jumper

1/2 m V² + 1/2 k x² = mg x

.5 x 60 x V² + .5 x 800 x .735 x .735 = 60 x 9.8 x .735

30 V² + 216.09 = 432.18

V = 2.68 m / s

b ) At lowest point , kinetic energy is zero and loss of potential energy will be equal to stored elastic energy.

1/2 k x² = mgx

x = 2 m g / k

= (2 x 60 x 9.8) / 800

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3 0
3 years ago
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Given that the wavelengths of visible light range from 400 nm to 700 nm, what is the highest frequency of visible light? (ccc =
enot [183]

7.5 × 10¹⁴ Hz is the highest frequency of visible light when wavelengths of visible light range from 400 nm to 700 nm.

The distance a wave travels in one unit of time is known as the wave speed (v).Taking into account that the wave travels one wavelength in one interval,

v=λ/T

Given that T = 1/f, we can write the equation above as,

V = f λ

Given data:

Minimum wavelength of visible light = 400 nm = 4 × 10⁻⁷ m

Speed of light = 3 × 10⁸ m/s

Frequency = c/λ = 3 × 10⁸ / 4 × 10⁻⁷

= 7.5 × 10¹⁴ Hz

To learn more about Frequency: brainly.com/question/16200748

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D. A bargain hunter purchases a "gold" crown at a flea market. After she gets home, she hangs it from a scale and finds its weig
s2008m [1.1K]

Answer:

Wc = 7.84    weight of crown

Ww = 7.84 - 6.86 = .98       weight of water displaced

Density = 7.84 / .98 = 8     crown is 8 X that of water

Since gold has a density of 19.3 that of water the crown is certainly not 100 percent (if any) gold  

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