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3 years ago

How do you estimate 12.062g to the nearest tens of a gram

Mathematics

1 answer:

gtnhenbr [62]3 years ago

6 0

12.602 = 10g
or if you meant tenTHs it will be 13g

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The rational number that expresses a loss of $25.30 is

Nezavi [6.7K]

Answer is 8 hope this helps

5 0

3 years ago

Three students, Matthew, Thompson and Amos shared #15000 in the ratio of 5:2:x respectively. If Matthew's share is 7500, calcula

jasenka [17]

Answer:

The value of x is 3.

Step-by-step explanation:

Matthew earned 7500 of 15000, which is exactly half the total amount, meaning that the fraction corresponding to his earnings is 1/2.

Rate of 5:2:x, with number 5 corresponding to Matthew, mean that his fraction of the earnings, in function of x is given by:

$\frac{5}{5 + 2 + x} = \frac{5}{7 + x}$

Both fractions are equal, so:

$\frac{5}{7 + x} = \frac{1}{2}$

Applying cross multiplication:

$7 + x = 10$

$x = 10 - 7$

$x = 3$

The value of x is 3.

5 0

3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

<em><u>Therefore, the two roots are:</u></em>

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago

Write an equation using “” and then solve the equation. The late fee for each day is $2. A patron paid $72 for books that are ov

topjm [15]

Pretty simple equation, where we need to find the number of books. If it is 2$ each day per book
72/9 = 8$ per day is the late fee paid
So if each book is 2$, then we can assume
8/2 = 4 books

So equation is
“# books = (amount paid)/(days * per day payment)”

4 0

2 years ago

Which is the graph of y = sqrt x-3

Greeley [361]

<h3>Answer: Choice B</h3>

The parent function y = sqrt(x) has the point (0,0) on it. When we subtract 3, we get y = sqrt(x)-3 which moves the point (0,0) three units down to get to (0,-3)

So (0,-3) is one point on y = sqrt(x)-3

7 0

3 years ago

Read 2 more answers