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Margaret [11]
3 years ago
8

When an apple falls towards the earth,the earth moves up to meet the apple. Is this true?If yes, why is the earth's motion not n

oticeable?
Physics
1 answer:
Harlamova29_29 [7]3 years ago
6 0

Answer:

because the mass of the apple is very less compared to the mass of earth. Due to less mass the apple cannot produce noticable acceleration in the earth but the earth which has more mass produces noticable acceleration in the apple. thus we can see apple falling on towards the earth but we cannot see earth moving towards the apple.

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Given: G = 6.672 × 10−11 N · m2 /kg2 Io, a satellite of Jupiter, has an orbital period of 1.24 days and an orbital radius of 4.1
Dahasolnce [82]

Answer:

Mass of Jupiter = 4.173×10^15kg

Explanation:

Using Kepler's 3rd law, it states that the orbital period T is related to the distance,r as:

T^2 = GM/4 pi × r^3

Where G = universal gravitational constant

r = radius

M = masd of jupiter

Rearranging the formular to make M the subject of formular

T^2 × 4 pi = G M × r^3

(T^2 × 4 pi) / (G× r^3) = M

(1.24^2 × 4 × 3.142) /(6.672×10^-11)(4.11×10^8)^3

M = 19.32 /6.672×10^-11)(4.11×10^8)^3

M = 19.32 / 4.63 ×10^15

M = 4.173×10^15kg

6 0
3 years ago
For which medical procedure would Doppler ultrasound be most useful?
Anestetic [448]
The answer is d.

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4 0
3 years ago
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A plane is travelling at 250km/h and must reach a target that is 3h 58min away. The distance to the target is. *
wariber [46]

Answer:

B) 89500 km

Explanation:

speed = distance / time

time= 3h 58 min = 30+58/60= 30.966 h = 31 hrs (approxx)

250= distance / 31

250× 31= distance

distance = 7750 ( approxx)

but none of the given options is 7750 km so we will choose the answer nearest to it,

therefore 89500km is the right answer

5 0
3 years ago
(II) A 0.72-m-diameter solid sphere can be rotated about an axis through its center by a torque of 10.8 m • N which accelerates
kozerog [31]

Answer:

m = 23.3 kg

Explanation:

As we know that it will have constant torque on it

so the acceleration of the ball will be constant so here we can say that we can use kinematics equation

\theta = \omega_i t + \frac{1}{2}\alpha t^2

160(2\pi) = 0 + \frac{1}{2}\alpha (15^2)

320 \pi = 112.5 \alpha

so we have

\alpha = \frac{320\pi}{112.5}

\alpha = 8.94 rad/s^2

now we know that

\tau = I \alpha

10.8 = I(8.94)

I = 1.21 kg m^2

so we know that

I = \frac{2}{5}mR^2

here we know that

diameter = 0.72 m

so radius (R) = 0.36 m

\frac{2}{5}m(0.36^2) = 1.21

m = 23.3 kg

8 0
3 years ago
An object has a mass of 0.250 kg. What is the gravitational force of on the object by the earth?
sesenic [268]

Answer:

2.4525 N

Explanation:

The earths gravity is 9.81 N/Kg

And so to work this out you would multiply 9.81 by 0.250 which equals to 2.4525N

7 0
4 years ago
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