Question

An ostrich lays the largest bird egg. A typical diameter for an ostrich egg at its widest part (diameter) is 12 cm (0.12 m). Suppose an egg of this size rolls
down a slope so that the centripetal acceleration of the shell at its widest part is 0.28 m/s2. What is the tangential speed of that part of the shell?

Answer 1

The centripetal acceleration is the ratio of the tangential speed and the

radius of the shell.

The tangential speed of the part of the shell is approximately 0.12961 m/s

Reasons;

The widest diameter of the egg, d = 12 cm = 0.12 m

The given centripetal acceleration, $a_c$ = 0.28 m/s²

Required:

The tangential speed of the bird.

Solution;

$\displaystyle Centripetal \ acceleration, \ a_c = \mathbf{\frac{v^2}{r}}$

Where;

$\displaystyle r = The \ radius \ of \ the \ egg \ shell = \frac{d}{2}$

v = The tangential speed

Which gives;

$\displaystyle r = \frac{0.12}{2} = 0.06$

$\displaystyle 0.28 \, m/s^2 = \frac{v^2}{0.06 \, m}$

v² = 0.28 m/s² × 0.06 m = 0.0168 m²/s²

v = √(0.0168 m²/s²) ≈ 0.12961 m/s

The tangential speed, v = 0.12961 m/s

Learn more about centripetal acceleration here:

brainly.com/question/79801