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ryzh [129]
3 years ago
8

A 40,000 kg locomotive is moving at a velocity of 11 m/s east. What is the magnitude of the locomotive's momentum? A. 440,000 kg

m/s B. 480,000 kg m/s C. 3,636 kg m/s D. 495,000 kg m/s
Physics
1 answer:
Reika [66]3 years ago
7 0
Momentum=mass*velocity=40,000*11=440,000 kg m/s. A
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An electron is released from rest in a weak electric field given by E =-2.30 x 10-10 N/Cj. After the electron has traveled a ver
Goshia [24]

Explanation:

It is given that,

An electron is released from rest in a weak electric field of, E=2.3\times 10^{-10}\ N/C

Vertical distance covered, s=1\ \mu m=10^{-6}\ m

We need to find the speed of the electron. Let its speed is v. Using third equation of motion as :

v^2-u^2=2as

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F=9.1\times 10^{-31}\times 9.8+1.6\times 10^{-19}\times 2.3\times 10^{-10}

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a=\dfrac{4.57\times 10^{-29}\ N}{9.1\times 10^{-31}\ kg}

a=50.21\ m/s^2

Put the value of a in equation (1) as :

v=\sqrt{2as}

v=\sqrt{2\times 50.21\times 10^{-6}}

v = 0.010 m/s

So, the speed of the electron is 0.010 m/s. Hence, this is the required solution.

6 0
4 years ago
Substances have more kinetic energy in the ______ state than in the ______ state.
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an airplane travels 2100 km at a speed of 1000 km/h for the next 1300 km. whatis the average speed for this plane trip?
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3 years ago
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