Question

The 0.41-kg cup of a James Bond anti-Martini-Maker is attached to a spring of spring constant 110 N/m. The cup is displaced horizontally from the equilibrium position and let go. What is the period of martini oscillation? A) 0.023 s B) 0.38 s C) 0.80s D) 100 s

Answer 1

Answer:

Option B is the correct answer.

Explanation:

Period of a spring is given by the expression

            $T=2\pi \sqrt{\frac{m}{k}}$

Here, spring constant, k = 110 N/m

         Mass = 0.41 kg

Substituting,

        $T=2\pi \sqrt{\frac{m}{k}}=2\pi \sqrt{\frac{0.41}{110}}=0.38s$

Option B is the correct answer.