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AURORKA [14]
3 years ago
9

There are six books in a stack, and each book weighs 5 N. The coefficient of static friction between the books is 0.2. With what

horizontal force must one push to start sliding the top five books off the bottom one? a. 1 N c. 3 N b. 5 N d. 7 N
Physics
2 answers:
Bezzdna [24]3 years ago
7 0

Answer:

5n

Explanation:

NikAS [45]3 years ago
3 0

Answer:

b. 5 N

Explanation:

Each book weighs 5 N.  Therefore, five books weigh 25 N.  The friction force is:

Ff = Fn μ

Ff = (25 N) (0.2)

Ff = 5 N

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4 0
3 years ago
arzan, who weighs 700 N, swings from a cliff at the end of a convenient vine thatis 20 m long. From the top of the cliff to the
vekshin1

Answer:

= 7.07 m

Explanation:

The Tarzan reaches bottom of swing after descending 2.5 m,

change in his potential energy equals his kinetic energy at bottom of swing

m g h = (1/2) m v²   ,  

hence speed v of Tarzan at bottom of swing is given as  

v = ( 2 g h )1/2

= ( 2 × 9.8 × 2.5 )1/2

= 7 m/s

At the bottom of swing, if the vine breaks, then he is moving with horizontal velocity 7 m/s in gravitational field.  

If vertical distance from ground to bottom of swing is 5 m, then time t for Tarzan to reach ground is given by

S = (1/2)g t2 or   t = (2S/g)1/2

= ( 2 × 5 / 9.8 )1/2

= 1.01 s

Horizontal distance traveled by Tarzan = 1.01 × 7

= 7.07 m

7 0
3 years ago
A ball is projected upward at time t = 0.0 s, from a point on a roof 70 m above the ground. The ball rises, then falls and strik
pentagon [3]

Answer:

The velocity of a ball will be "-70.13 m/s".

Explanation:

The given values are:

u = 70 m

t = 0.0 s

g = a = -9.8 m/s²

s = -1 m

v = ?

As we know,

The equation of motion will be:

⇒  v^2-u^2=2as

On substituting the estimated values, we get

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⇒  v^2=4919.6

⇒  v=\sqrt{4919.6}

⇒  v=70.13 \ m/s

In downward direction, it will be:

⇒  v=-70.13 \ m/s

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11111nata11111 [884]

Answer:

chiicken

Explanation:

5 0
3 years ago
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