Answer : The amount of heat changes is, 56.463 KJ
Solution :
The conversions involved in this process are :
Now we have to calculate the enthalpy change.
where,
= enthalpy change or heat changes = ?
n = number of moles of water = 1 mole
= specific heat of solid water =
= specific heat of liquid water =
= specific heat of liquid water =
m = mass of water
= enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole
= enthalpy change for vaporization = 40.67 KJ/mole = 40670 J/mole
Now put all the given values in the above expression, we get
(1 KJ = 1000 J)
Therefore, the amount of heat changes is, 56.463 KJ