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Irina-Kira [14]
3 years ago
6

A mixture with medium sized particles that do not settle out is called

Chemistry
1 answer:
Alexandra [31]3 years ago
7 0

Answer: colloid

Explanation:

Colloids are solutions in which small sized particles are suspended throughout the solution as they do not settle own their own. Colloids are defined as the mixtures where the size of the particle is within the range of 2nm to 1000 nm. In these mixtures, physical boundary is seen between the dispersed phase and dispersed medium.

Colloids are solutions with particle size intermediate between true solutions and suspensions. Suspensions have large sized particles which settle when left undisturbed for sometime and thus can be filtered off easily. The particle size in colloids is less and hence they do not settle under the effect of gravity.

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4. Determine what elements are in the following compounds.
lilavasa [31]
Nitrogen=2, Hydrogen=8, Carbon=1, Oxygen=3

Hydrogen=4, Carbon=2, Oxygen=2

Iron=1, Nitrogen=2, Oxygen=6
8 0
3 years ago
What is the volume, in mL, of 0.50 moles of ammonia (NH3) at STP?
blagie [28]
For the purpose we will here use the ideal gas law:

p×V=n×R×T

V= ?
n = 0.5 moleT= 273.15 K (at STP)
p= 101.325 kPa (at STP)
R is  universal gas constant, and its value is 8.314 J/mol×K

Now when we have all necessary date we can calculate the number of moles:
V=nxRxT/p
V=0.5x8.314x273.15/101.325= 11.2 L = 11200 mL

Answer: D.
5 0
3 years ago
1-bromo-2-chloro-4-propylpentene
Nonamiya [84]
..:)../:................

3 0
3 years ago
URGENT
Vadim26 [7]

Answer:

Explanation:

Discussion

When Pressure increases  equilibrium shifts to the side with the smallest number of moles. But which side is that?

N2(g) + 3H2(g) ⇌ 2NH3(g)

The left side has 1 mol of nitrogen (N2) and 3 moles of Hydrogen = 4 mols

on the left side.

The right side has 2 mols of NH3 = 2 mols on the right.

Conclusion: You tell the number of mols by the Balance numbers to the left of each chemical in an equation.

Since the left side N2 + 3H2 = 4 mols, the equilibrium does NOT shift left.

2NH3 is only two mols.

The equilibrium shifts Right

Answer

D

7 0
2 years ago
The student's lab manual says to mix some of his Na2CO3 solution with an aqueous solution of copper(II) sulfate (CuSO4)
lord [1]

Explanation:

When the student mixed the solution sodium carbonate with solution of copper(II) sulfate ; Copper Hydroxocarbonate , sodium sulfate and carbon dioxide gas was obtained as a products.

The balanced chemical reaction

2Na_2CO_3+2CuSO_4\rightarrow Cu_2(OH)_2CO_3+2Na_2SO_4+CO_2

Where:

Cu_2(OH)_2CO_3 = Copper(II) Hydroxocarbonate

Na_2CO_3 = Sodium carbonate

CuSO_4 = Copper(II) sulfate

Na_2SO_4 = Sodium sulfate

CO_2 = Carbon-dioxide

3 0
3 years ago
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