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Phoenix [80]
3 years ago
14

Sum up in a few sentences what did Cavendish discover and how did he do it?

Physics
1 answer:
exis [7]3 years ago
8 0
He was a British philosopher, and an important experimental and theoretical chemist. He is known for his discovery of hydrogen. He at that time called it "inflammable air".
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Help ASAP!<br> Everything on screenshot
BARSIC [14]

Answer:

For the first one, its B) cities B and C

I'm not so sure, but I hope this helps.

7 0
3 years ago
What is the speed of terminal velocity?
ivann1987 [24]
The so-called "terminal velocity" is the fastest that something can fall
through a fluid.  Even though there's a constant force pulling it through,
the friction or resistance of plowing through the surrounding substance
gets bigger as the speed grows, so there's some speed where the resistance
is equal to the pulling force, and then the falling object can't go any faster.

A few examples:
-- the terminal velocity of a sky-diver falling through air,
-- the terminal velocity of a pecan falling through honey,
-- the terminal velocity of a stone falling through water.

It's not possible to say that "the terminal velocity is ----- miles per hour".
If any of these things changes, then the terminal velocity changes too:

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4 0
3 years ago
The force diagram represents a girl pulling a sled with a mass of 6.0 kg to the left with a force of 10.0 N at a 30.0 degree ang
STatiana [176]

the correct answers are 54N and -1,2m/s^2

6 0
3 years ago
Read 2 more answers
Which of the following indicates a heat transfer?
lesya [120]

Answer:

TEMPERATURE CHANGES

Explanation:

WELL ITS BASIC. WHEN TEMPERATURE CHANGES. IT MEANS THAT HEAT IS BEING TRANSFERRED AS I HEARD THAT COLD CANNOT BE TRANSFERRED

3 0
3 years ago
The masses of the two moons are determined to be 2M2M for Moon AA and MM for Moon BB . It is observed that the distance between
seraphim [82]

Answer:

 F_A = 8 F_B

Explanation:

The force exerted by the planet on each moon is given by the law of universal gravitation

        F = G \frac{m M}{r^{2} }

where M is the mass of the planet, m the mass of the moon and r the distance between its centers

let's apply this equation to our case

Moon A

the distance between the planet and the moon A is r and the mass of the moon is 2m

        F_A = G \frac{2m M}{r^{2} }

Moon B

        F_B = G \frac{m M}{(2r)^{2} }

         F_B = G \frac{m M}{4 r^{2} }

the relationship between these forces is

         F_B / F_A = \frac{1}{2 \ 4 } = 1/8

         F_A = 8 F_B

7 0
3 years ago
Read 2 more answers
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