Answer:
a) v = √(v₀² + 2g h), b) Δt = 2 v₀ / g
Explanation:
For this exercise we will use the mathematical expressions, where the directional towards at is considered positive.
The velocity of each ball is
ball 1. thrown upwards vo is positive
v² = v₀² - 2 g (y-y₀)
in this case the height y is zero and the height i = h
v = √(v₀² + 2g h)
ball 2 thrown down, in this case vo is negative
v = √(v₀² + 2g h)
The times to get to the ground
ball 1
v = v₀ - g t₁
t₁ =
ball 2
v = -v₀ - g t₂
t₂ = - \frac{v_{o} + v }{ g}
From the previous part, we saw that the speeds of the two balls are the same when reaching the ground, so the time difference is
Δt = t₂ -t₁
Δt =
Δt = 2 v₀ / g
Answer:
im very con fused on what you mean by this
Explanation:
(sorry I can only answer no. 1)
the climate is the weather over a long period of time (could be days, weeks, months, or years) while weather is only how the day has been on one day (e.g. sunny)
Answer:
Explanation:
3.4 = 18.87x + 23.97
collecting like terms
3.4 - 23.97 = 18.87x
-20.57 = 18.87x
dividing both sides by 18.87
x = -20.57/18.87
x= -1.09