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Genrish500 [490]
3 years ago
12

A football is kicked from ground level with an initial velocity of 23.6 m/s at angle of 57.5° above the horizontal. How long, in

seconds, is the football in the air before it hits the ground? Ignore air resistance.
Physics
1 answer:
aniked [119]3 years ago
3 0

Answer:

6 seconds is the best answer

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An atom is the most __________ unit of living and nonliving things.
storchak [24]
Basic is the answer. (i think so) 
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3 years ago
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A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 800.0 kg t
Stella [2.4K]

Answer:

Explanation:

mass of car, m1 = 1170 kg

mass of truck, m2 = 9800 kg

initial velocity of car, u1 = 25 m/s

initial velocity of truck, u2 = 20 m/s

final velocity of car, v1 = 18 m/s

Let the final velocity of truck is v2.

(a) Use the conservation of momentum

m1 x u1 + m2 x u2 + m1 x v1 + m2 x v2

1170 x 25 + 9800 x 20 = 1170 x 18 + 9800 x v2

29250 + 196000 = 21060 + 9800 v2

v2 = 20.84 m/s

(b) Total kinetic energy before collision,

Ki = 0.5 x 1170 x 25 x 25 + 0.5 x 9800 x 20 x 20

Ki = 365625 + 1960000 = 2325625 J

Total final kinetic energy

Kf = 0.5 x 1170 x 18 x 18 + 0.5 x 9800 x 20.84 x 20.84

Kf = 189540 + 2128097.44

Kf = 2317637.44 J

Change in energy = 2325625 - 2317637.44 = 7987.56 J

(c) It is due to the heat energy

4 0
3 years ago
An object with a mass of 2.0 kg accelerates 2.0 m/s2 when an unknown force is applied to it. What is the amount of the force?​
Alinara [238K]

Answer:

4 Newton’s

Explanation:

7 0
2 years ago
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1. How is electric potential energy similar to gravitational potential energy? How is it different? Where will an electron bound
Korolek [52]
Both ve similar equations 
<span>both are energies of one object w.r.t another </span>
<span>differences- electric pe is due to electrostatic force and gravitational pe is due to gravitational force </span>
<span>electric pe is > than gravitational pe since electrostatic force> gravitational force </span>
<span>electron bound in an atom ll ve largest potential enegy in its ground state. i think hope it helps</span>
7 0
3 years ago
A 300 gg bird flying along at 5.7 m/sm/s sees a 10 gg insect heading straight toward it with a speed of 29 m/sm/s (as measured b
liberstina [14]

Answer:

bird's speed  = 4.58 m/s

Explanation:

given data

mass of bird mb = 300 g

velocity of bird vb = 5.7 m/s

mass of insect mi = 10 g

velocity of insect vi = - 29 m/s

solution

here momentum of system is constant

we apply here conservation of momentum so

mb × v + mi × v = mb × vb + mi × vi   ....................1

v ( mb + mi ) = mb × vb + mi × vi  

put here value and we get

v ( 300 + 10 ) = { 300 × 5.7 }  +  { 10 × (-29) }

v = \frac{1710-290}{310}  

v = 4.58 m/s

8 0
3 years ago
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