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Alenkinab [10]
3 years ago
14

A 0.70kW vacuum cleaner is used for 20 minutes. How much energy does it use? Give your answer in

Physics
2 answers:
sweet-ann [11.9K]3 years ago
7 0

20 minutes = 20/60 = 0.33 hr

0.7 kw * 0.33 hr = 0.231 kWh = 0.23 kWh

Plz mark as Brill

ad-work [718]3 years ago
4 0

Answer:

0.23kw

Explanation:

none

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4. With respect to a mass of 1kg. (a) How much change in elevation must it undergo to change its potential energy by 1 kJ? (g=9.
mojhsa [17]

Answer:

102 m upwards.

Explanation:

Just from a qualitative analysis we can tell the mass it needs to go upwards. How much we determine with the fact that the increase will be - in absolute value - equal to the work gravity does on it to go down that same distance.

Fixed that work being 1 kJ, we get

\vec F \cdot \vec{ \Delta h} = |F| |\Delta h| cos 0 = ( 9.8 N )\Delta h \cdot 1 = 10^3 J\\\Delta h = \frac {10^3}{9,8} m \approx 102 m

4 0
2 years ago
Please help on this one?
pashok25 [27]

Answer:

B) It is connected in parallel and measures potential differences.

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Hope this helps! :)

7 0
3 years ago
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