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3 years ago

How do the sun energy flow through the earth system

Physics

1 answer:

storchak [24]3 years ago

5 0

The sun's energy flow through the earth's system by it moving through the earth's atmosphere.

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The dimensions of aluminum foil in a box for sale in super markets are 66 2/3 yards by 12 inches. the mass of the foil is 0.83 k

disa [49]

Length of the sheet is given as

$L = \frac{200}{3} yards = 6096 cm$

width of the sheet is given as

$w = 12 inches = 30.48 cm$

now let say its thickness is "t"

so the volume of the sheet is given as

$V = L*w*t$

$V = 6096*30.48* t$

$V = 185806.08*t cm^3$

mass of the sheet is given as

$m = 0.83 kg = 830 gram$

now we have

$density = \frac{mass}{volume}$

$2.70 = \frac{830}{185806.08*t}$

by solving above we have

$t = 1.65 * 10^{-3} cm$

so the thickness of sheet will be above

4 0

3 years ago

A temperature of a 50 kg block increases by 15°C when 337,500 J thermal energy are added to the block. what is the block made of

DENIUS [597]

Answer:

Iron

Explanation:

H = mc∅

Above equation can be used here to find the answer to the question. this equation gives us the relationship between the heat energy supplied to a material and the temperature difference that the material would go through according to its mass.

here H is the Heat energy supplied to the material. m is the mass of the material. c is the specific heat capacity of the material and ∅ is the temperature difference applied to the material. we are given that H= 337,500J , m = 50 kg and ∅ = 15 °C. so from the equation now we can calculate the value of c. after calculating c we can find the material because c is an unique value for a particular material. no two materials have the same c value.

c = 337500/(50*15)

c = 450 J/(kg°C) - Iron (google the heat capacity value to find the answer Iron)

8 0

3 years ago

A tiny particle with charge + 5.0 μC is initially moving at 55 m/s. It is then accelerated through a potential difference of 500

Vadim26 [7]

Answer:

ΔK.E = 2.5 × 10⁻³ J

Explanation:

Given data in the question, we have:

Charge of the particle, q = 5.0 μC = 5 × 10 ⁻⁶ C

Initial speed of the particle, v = 55 m/s

The potential difference, ΔV = 500 V

Now, the gain in kinetic energy is given as

ΔK.E = q × ΔV

on substituting the values in the above formula, we get

ΔK.E = 5 × 10 ⁻⁶ C × 500 V

ΔK.E = 2.5 × 10⁻³ J

8 0

3 years ago

For rectilinear motion the relationship between displacement, s, velocity, v, acceleration, a, and time, t, s = s0 + v0t + (1/2)

stiv31 [10]

The rectilinear motion is given as:

s = s0 + v0 t + (1/2) a t^2

We can see that the variables stand for:

s = final distance

s0 = initial distance

v0 = initial velocity

t = time

a = acceleration

<span>We can see that all these variable are always constant EXCEPT acceleration. The rectilinear motion can only be applied if and only if acceleration is CONSTANT.</span>

6 0

3 years ago

Problem 28.3 Suppose that you are planning a trip in which a spacecraZ is to travel at a constant velocity for exactly six month

iragen [17]

Answer:

v = 0.999981c m/s

Explanation:

Using the time dilation equation

$T = \frac{T_{0} }{\sqrt{1 - \frac{v^{2} }{c^{2} } } }$

T = stationary time = 100 years

T₀ = 11/12 years = 0.917 years

v = speed of travel in the space = ?

c = speed of light = 3 * 10⁸ m/s

$100 = \frac{0.917 }{\sqrt{1 - \frac{v^{2} }{(3*10^{8} )^{2} } } }\\$

$(0.917/100) ^{2} = 1 - \frac{v^{2} }{ 9 * 10^{16} }$

v = 299987395.57 m/s

v = 2.99 * 10⁸ m/s

v = 0.999981c m/s

3 0

3 years ago