give an example of situation in which an automobile driver can have a centripetal acceleration but no tangential speed
1 answer:
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Answer:
The new voltage between the parallel plates of the capacitor is 18V, because for a constant electric field, doubling the space between the parallel capacitor plates, will also double the potential difference (voltage) between the plates.
Explanation:
ΔV = E*Δd
Where;
ΔV is the change in potential difference
Δd is the change in the distance between the parallel plates
E is the electric field potential.
Assuming a constant electric field;
when the spacing between the capacitor plates is doubled, d₂ = 2d₁
v₂ = (v₁*d₂)/(d₁)
v₂ = (v₁*2d₁)/(d₁)
v₂ = 2v₁
v₂ = 2(9) = 18 V
Therefore, for a constant electric field, doubling the space between the parallel capacitor plates, will also double the potential difference (voltage).
Answer:
Part A
The angular speed of rotation of the plane is 8.11781 × 10⁻⁵ rad/s
Part B
The angular speed of orbit of the planet is 1.04938 × 10⁻⁶ rad/s
Explanation:
The parameters of the planet are;
The duration of a day on the distant planet = 21.5 hr.
The duration of a year on the distant planet = 69.3 Earth days
Part A
The duration of a day = The time to make one complete revolution of 2·π radians
∴ The average angular speed about its axis, = Angle turned/Time
∴ = 2·π/(21.5 × 60 × 60) s ≈ 8.11781 × 10⁻⁵ rad/s
The average angular speed of the planet about its own axis, = 8.11781 × 10⁻⁵ rad/s
The angular speed of rotation of the plane = 8.11781 × 10⁻⁵ rad/s
Part B
The time it takes the planet to revolve round the neighboring star once = 69.3 Earth days
Therefore, the average angular speed of the planet around its neighboring star, , is given as follows;
= 2·π/((69.3 × 24 × 60 × 60) s) = 1.04938 × 10⁻⁶ rad/s
The average angular speed of orbit, = 1.04938 × 10⁻⁶ rad/s
The angular speed of orbit of the planet, = 1.04938 × 10⁻⁶ rad/s.