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1 year ago

give an example of situation in which an automobile driver can have a centripetal acceleration but no tangential speed

Physics

1 answer:

Mars2501 [29]1 year ago

6 0

There is no need for tangential acceleration when moving in a circle at a constant speed.

<h3>What is centripetal acceleration?</h3>

centripetal acceleration refers to the speed at which a body moves through a circle. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude, the speed, and a direction), when a body travels in a circle, its direction is constantly changing, which causes a change in velocity, which results in an acceleration.

<h3>Which is an example of centripetal acceleration?</h3>

Centripetal acceleration occurs when you spin a ball on a string above your head. A car experiences centripetal acceleration when it is being driven in a circle. Additionally, a satellite in orbit around the Earth experiences centripetal acceleration.

To know more about tangential acceleration :

brainly.com/question/14993737

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What is the acceleration of a 349 kg object that moved with a force of 750 N?

zavuch27 [327]

Answer:

<h3>The answer is 2.15 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

where

f is the force

m is the mass

From the question we have

$a = \frac{750}{349} \\ = 2.14899713...$

We have the final answer as

Hope this helps you

4 0

3 years ago

An 800-g block of ice at 0.00°C is resting in a large bath of water at 0.00°C insulated from the environment. After an entropy c

Allisa [31]

Answer:

Unmeltedd ice = 308.109 g

Explanation:

Gibbs Free energy:

A systems Gibbs Free Energy is defined as the free energy of the product of the absolute temperature and the entropy change less than the enthalpy change.

Therefore, G = ΔH-TΔS

where G is Gibbs Free Energy

ΔH is enthalpy change

T is absolute temperature

ΔS is entropy change

Here since there is a phase change, therefore G will be 0.

∴ΔH = TΔS

Given: Temperature, T = 0°C = 273 K

Entropy change,ΔS = 600 J/K

Latent heat of fusion of water = 333 J/g

∴ΔH = TΔS

∴ΔH = 273 x 600

= 163800 J

So this is the amount of enthalpy that will be used into melting of ice.

∴ΔH = mass of ice melted x latent heat of fusion of water

Mass of ice melted = ΔH / latent heat of fusion of water

= 163800 / 333

= 491.891 g

This is the mass of ice melted.

And initial amount of ice is 800 g

Amount of ice left after melting = Initial amount of ice - amount of ice melted

= 800-491.891

= 308.109 g

Amount of ice remained after melting = 308.109 g

8 0

3 years ago

A motorboat maintained a constant speed of 15 miles per hour relative to the water in going 10 miles upstream and then returning

Lesechka [4]

Answer:

speed of current is 5 mile/hr

Explanation:

GIVEN DATA:

speed of motorboat = 15 miles/hr relative with water

let c is speed of current

15-c is speed of boat at upstream

15+c is speed of boat at downstream

we know that

travel time=distance/speed

$\frac{10}{15-c} +\frac{10}{15+c} = 1.5$

150+10c+150-10c=1.5(15-c)(15+c)

300=1.5(225-c^2)

300=337.5-1.5c^2

200=225-c^2

c^2=25

c = 5

so speed of current is 5 mile/hr

6 0

3 years ago

When lights are wired such that if one bulb fails, the entire string of lights

Viktor [21]

Answer:

series

Explanation:

In a series circuit all the components are attached to one branch, so that if one component fails, all the others stop working. In a parallel circuit, however, the components are wired in separate branches, so that even if one branch fails, the rest are not disrupted.

8 0

2 years ago

Read 2 more answers

The bellow of a territorial bull hippopotamus is measured at 100 dB above the threshold of hearing. What is the sound intensity?

Dmitriy789 [7]

Answer:

Explanation:

The hippopotamus hearing threshold is 100dB

β = 100 dB

The threshold of human hearing is Io = 1 × 10^-12 W/m²

The sound intensity level is given as

β = 10•Log(I / Io)

100 = 10•Log(I / Io)

Divided Both sides by 10

100 / 10 = Log(I / Io)

10 = Log(I / Io)

Take inverse Logarithm ( antilog) of both sides

10^10 = 10^[Log(I / Io)]

10^10 = I / Io

Then,

I = 10^10 × Io

I = 10^10 × 1 × 10^-12

I = 1 × 10^-2 W/m²

I = 0.01 W/m²

The sound intensity is 0.01 W/m²

5 0

3 years ago