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podryga [215]
2 years ago
11

if .709 j of heat is added to water and cause the temperature to go up by .036 degrees C what mass of water is present

Chemistry
1 answer:
liberstina [14]2 years ago
8 0

Answer:

0.00471 grams H₂O

Explanation:

To determine the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = temperature change (°C)

The specific heat capacity of water is 4182 J/g°C. You can plug the given values into the equation and simplify to isolate "c".

Q = 0.709 J                            c = 4182 J/g°C

m = ? g                                   ΔT = 0.036 °C

Q = mcΔT                                                    <----- Equation

0.709 J = m(4182 J/g°C)(0.036 °C)            <----- Insert values

0.709 J = m(150.552)                                 <----- Multiply 4182 and 0.036

0.00471 = m                                              <----- Divide both sides by 150.552

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Nesterboy [21]

Answer:

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Explanation:

This is a single replacement equation where there are 2 metals. The bonds are broken and new bonds are formed again by Mg and F.

Er has a +3 charge and F has a -1 charge. You switch it around and you get ErF3. Then you add the second reactant, Mg. The product is MgF as stated, and Mg has a charge of +2 and F has -1. You switch it again and you get MgF2. Then the second product Er is there.

Now we have

ErF3+Mg=MgF2+Er

So we balance the equation because of the law of conservation of mass.

Make F equal, so we add the coefficents 2 and 3

2ErF3+Mg=3MgF2+Er

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2ErF3+3Mg=3MgF2+2Er

Hope this helped

8 0
3 years ago
Why does the water seem cooler in the day and warmer at night?
Otrada [13]

Answer:

Not much heat moves into the lower levels of the ground. The heat that the ocean absorbs is mixed with the lower water quickly. ... At night, while the land cools off quickly, the water at the surface is kept warmer because the water is mixed around with the warmer water underneath.

4 0
3 years ago
After an afternoon party, a small cooler full of ice is dumped onto the hot ground and melts. If the cooler contained 6.60 kg of
gtnhenbr [62]

Answer:

The quantity of heat required to melt all the ice at 0°C is 2.21 * 10⁶ J

Explanation:

Latent heat of fusion  is the heat absorbed by a unit mass of a given solid at its melting point that completely converts the solid to a liquid at the same temperature. Its unit is Joules/kg or Joules/g.

1 calorie = 4.184 Joules

Therefore , 80.0 cal/g = 80.0 cal/g * 4.184 J/cal = 334.72 J/g

1 g = 0.001 kg; Heat of fusion in J/kg = 334.72 J/g * 1g /0.001 kg = 3.35 * 10⁵ J/kg

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quantity of heat required = 6.60 kg * 3.35 * 10⁵ J/kg

Quantity of heat required = 2.21 * 10⁶ J

Therefore, the quantity of heat required to melt all the ice at 0°C is 2.21 * 10⁶ J

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6 0
4 years ago
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