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3 years ago

14

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1 answer:

umka21 [38]3 years ago

8 0

You would have to put the number together

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A 4.04 kg block slides down a smooth, frictionless plane having an inclination of 30◦. The acceleration of gravity is 9.8 m/s^2.

aleksandrvk [35]

Answer:

Explanation:

What a lot of words to solve such a simple problem! The perpendicular force is the one that is pushing straight down on the plane. There is no side to side movement here or friction acting on this dimension at all. Perpendicular force is the same as the weight of the block. That's it! Perpendicular force is also normal force which is the same thing as weight:

w = mg so

w = (4.04)(9.8) and

w = 4.0 × 10¹ N

5 0

3 years ago

Help me. It's question 2 I need the answer for

Alex73 [517]

Ok, let me see if I can help

Sound is caused by vibrations. These can pass through a solid, liquid, and gas. But not through vacuum because there are no particles

6 0

3 years ago

What is the highest energy of radiation?

ser-zykov [4K]

Gamma rays ..........................

6 0

4 years ago

A total charge of –6.50 µC is uniformly distributed within a sphere that has a radius of 0.150 m. What is the magnitude and dire

Marrrta [24]

Answer:

A) 2.89 × 105 N/C, radially inward

Explanation:

The magnitude of the electric field generated by a charged sphere is given by the following formula:

$E=k\frac{Q}{r^2}$ ( 1 )

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

Q: charge of the sphere = -6.50*10^-6 C

r: distance from the center of the sphere to the point in which E is calculated

r = 0.150m + 0.300m = 0.450 m

You replace the values of Q and r in the equation (1):

$E=(8.98*10^9Nm^2/C^2)\frac{6.50*10^{-6}C}{(0.450m)^2}=288246.91\frac{N}{C}\\\\E\approx2.89*10^5\frac{N}{C}$

The electric field points radially inward because the charge is negative.

hence, the answer is:

A) 2.89 × 105 N/C, radially inward

7 0

4 years ago

8.92 A 45.0 kg woman stands up in a 60.0 kg canoe 5.00 m long. She walks from a point 1.00 m from one end to a point I .00 m fro

omeli [17]

The distance that the canoe moves in this process is 1.29 meters.

We first have to find the center of mass

$X = \frac{MsXs+McXc}{Mw+Mc} \\\\$

Where

Ms = Woman's mass = 45

Mc = Canoe's mass = 60kg

Xs = position from left= 1 cm

Xc = position from left end of canoe's mass = 2.5cm

When we put these values into the equation we have:

$X=\frac{45*1+60*2.5}{45+60} \\\\= 1.857\\$

The center of gravity lies at the center of this boat. Therefore,

$Xc = \frac{L}{2} \\\\L = 5 m long\\\\\frac{5}{2} =2.5$

5.00 - 1. 00 = 4 meters

$\frac{45*4+60*2.5}{45+60} = 3.14meters\\\\$

To get the distance that is moved by this canoe

distance = 3.143-1.857

= 1.286

≈ 1.29 meters

The distance that the canoe moves in this process is 1.29 meters.

Read more on brainly.com/question/13198009?referrer=searchResults

6 0

2 years ago