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Genrish500 [490]
3 years ago
9

The force between two very small charged bodies is found to be F. If the distance between them is tripled without altering their

charges, the force between them becomes
Physics
1 answer:
SpyIntel [72]3 years ago
6 0

Answer:

if the old force is F, the new force is F/9

Explanation:

Recall that the Coulomb force between to charges is inversely proportional to the square of the distance between the charges.

Therefore, if the original distance "d" changes now to be "3d" (tripled), the denominator of the force expression will change from:

d^2 \,\,\, to \,\,\,(3d)^2 = 9\,d^2

thus reducing the original force by a factor 1/9

So if the old force is F, the new force is F/9

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T₁ =  λ₁/c = 235 × 10⁻⁶ m/3 × 10⁸ m/s = 7.833 × 10⁻¹³ s = 0.7833 ps

T₂ = 2.8T₁ = 2.8 × 7.833 × 10⁻¹³ s = 21.93 × 10⁻¹³ s = 2.193 ps

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λ₂ = 2.8λ₁ = 2.8 × 235 μm = 658 μm

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B = E/c = E/λ₁/T₁ = ET₁/λ₁

B = ET₁/λ₁ = 3.30 × 10⁻³ V/m × T₁/235 × 10⁻⁶ m = 14.04T₁  Tesla

B = 14.04 × 7.833 × 10⁻¹³ s = 10.99 × 10⁻¹² T ≅ 11 pT

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91.21

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