The force between two very small charged bodies is found to be F. If the distance between them is tripled without altering their
1 answer:
Answer:
if the old force is F, the new force is F/9
Explanation:
Recall that the Coulomb force between to charges is inversely proportional to the square of the distance between the charges.
Therefore, if the original distance "d" changes now to be "3d" (tripled), the denominator of the force expression will change from:
thus reducing the original force by a factor 1/9
So if the old force is F, the new force is F/9
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<h2>Hello!</h2>
The answer is: 19.59 m
<h2>Why?</h2>Since there is no information about the launch type, we can assume that the ball is thrown vertically upward.
When the ball reaches the maximum height, just at that moment, the velocity turns to 0, and after that moment, the ball starts falling, so:
We will use the following formula:
Where:
Vf= Final velocity = 0
Vi= Initial velocity =
g = Gravity Acceleration =
s = Traveled distance
Have a nice day!