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Genrish500 [490]
3 years ago
9

The force between two very small charged bodies is found to be F. If the distance between them is tripled without altering their

charges, the force between them becomes
Physics
1 answer:
SpyIntel [72]3 years ago
6 0

Answer:

if the old force is F, the new force is F/9

Explanation:

Recall that the Coulomb force between to charges is inversely proportional to the square of the distance between the charges.

Therefore, if the original distance "d" changes now to be "3d" (tripled), the denominator of the force expression will change from:

d^2 \,\,\, to \,\,\,(3d)^2 = 9\,d^2

thus reducing the original force by a factor 1/9

So if the old force is F, the new force is F/9

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A 975-kg sports car (including driver) crosses the rounded top of a hill at determine (a) the normal force exerted by the road o
iVinArrow [24]
There are missing data in the text of the problem (found them on internet):
- speed of the car at the top of the hill: v=15 m/s
- radius of the hill: r=100 m

Solution:

(a) The car is moving by circular motion. There are two forces acting on the car: the weight of the car W=mg (downwards) and the normal force N exerted by the road (upwards). The resultant of these two forces is equal to the centripetal force, m \frac{v^2}{r}, so we can write:
mg-N=m \frac{v^2}{r} (1)
By rearranging the equation and substituting the numbers, we find N:
N=mg-m \frac{v^2}{r}=(975 kg)(9.81 m/s^2)-(975 kg) \frac{(15 m/s)^2}{100 m}=7371 N

(b) The problem is exactly identical to step (a), but this time we have to use the mass of the driver instead of the mass of the car. Therefore, we find:
N=mg-m \frac{v^2}{r}=(62 kg)(9.81 m/s^2)-(62 kg) \frac{(15 m/s)^2}{100 m}=469 N

(c) To find the car speed at which the normal force is zero, we can just require N=0 in eq.(1). and the equation becomes:
mg=m \frac{v^2}{r}
from which we find
v= \sqrt{gr}= \sqrt{(9.81 m/s^2)(100 m)}=31.3 m/s
7 0
3 years ago
A ruby laser delivers a 16.0-ns pulse of 4.20-MW average power. If the photons have a wavelength of 694.3 nm, how many are conta
stepan [7]

Answer:

The  value is  n  =  2.347 *10^{17} \  photons

Explanation:

From the question we are told that

     The  amount of power delivered is  P  =  4.20 \  M W  =  4.20  *10^{6} \  W

      The  time taken is  t =  16.0ns  =  16.0 *10^{-9} \  s

       The  wavelength is  \lambda  =  694.3 \  nm =  694.3 *10^{-9} \  m

     

Generally the energy delivered is  mathematically represented as

     E  =  P  * t  =  \frac{n  *  h  *  c  }{\lambda }

Where  h is the Planck's constant with value  h  =  6.262  *10^{-34} \  J \cdot  s

           c  is the speed of light with value  c =  3.0*10^{8} \  m/s

     

So  

    4.20 *10^{6}  *  16*10^{-9}=  \frac{n  *  6.626 *10^{-34}  *  3.0*10^{8}  }{694.3 *10^{-9}}

=>    n  =  2.347 *10^{17} \  photons

4 0
3 years ago
Johnny was playing baseball with his friends and they noticed a bolt of lightning. They heard thunder seven seconds later. How f
denis-greek [22]
The storm would be at least 7 miles away cause light travels faster than sound and you can tell how many miles away a lightning bolt might have hit by how long it takes the thunder to strike<span />
4 0
3 years ago
What is something that has a lot of thermal energy?
Artemon [7]
a heater that produces lots of warm air which would include thermal energy or a kitchen stove
8 0
3 years ago
Read 2 more answers
Convert 300mil per hr to km per hr​
Dominik [7]

Answer: 482.8032 km per hr

Explanation: 300 * 1.609344 =

3 0
3 years ago
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