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GuDViN [60]
3 years ago
14

How many molecules of ch4 are present in .41 moles

Chemistry
1 answer:
solong [7]3 years ago
8 0

Answer: 6.56g

Explanation:

No of moles = mass given/molar mass

Molar mass of ch4

C is carbon which is 12

H is hydrogen which is 1

Molar mass= 12+4(1)

Molar mass= 16g/moles

No of moles given is 0.41moles

No of moles = mass given/molar mass

Mass given = molar mass × no of moles

Mass given = 16×0.41

Mass= 6.56g

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- What is the concentration of hydrogen ions if the pH is 12?
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Consider the following reaction between mercury(II) chloride and oxalate ion.
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<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

where,

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b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

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Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b  ....(4)  

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\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2

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\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

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