Answer:
41.17g
Explanation:
We are given the following parameters for Flourine gas(F2).
Volume = 5.00L
Pressure = 4.00× 10³mmHG
Temperature =23°c
The formula we would be applying is Ideal gas law
PV = nRT
Step 1
We find the number of moles of Flourine gas present.
T = 23°C
Converting to Kelvin
= °C + 273k
= 23°C + 273k
= 296k
V = Volume = 5.00L
R = 0.08206L.atm/mol.K
P = Pressure (in atm)
In the question, the pressure is given as 4.00 × 10³mmHg
Converting to atm(atmosphere)
1 mmHg = 0.00131579atm
4.00 × 10³ =
Cross Multiply
4.00 × 10³ × 0.00131579atm
= 5.263159 atm
The formula for number of moles =
n = PV/RT
n = 5.263159 atm × 5.00L/0.08206L.atm/mol.K × 296K
n = 1.0834112811moles
Step 2
We calculate the mass of Flourine gas
The molar mass of Flourine gas =
F2 = 19 × 2
= 38 g/mol
Mass of Flourine gas = Molar mass of Flourine gas × No of moles
Mass = 38g/mol × 1.0834112811moles
41.169628682grams
Approximately = 41.17 grams.
Molar mass NaCl = 58.5 g/mol
C = 158.0 g/L
Molarity = C / molar mass
M = 158.0 / 58.5
M = 2.7000 M
hope this helps!
Answer:
Mostly large grains, with a sticky texture, 55% sand, 40% clay, and 5% silt
Explanation: I took the test, hope it helps.
Explanation:
Given parameters:
Number of molecules = 4.21 x 10²³ molecules
Unknown parameters:
Number of moles
Solution:
A mole can be defined as the amount of a substance that contains the avogadro's number of particles i.e 6.02 x 10²³
To find the number of moles:
Number of moles = ![\frac{number of molecules }{[tex]6.02 x 10^{23}](https://tex.z-dn.net/?f=%5Cfrac%7Bnumber%20of%20molecules%20%7D%7B%5Btex%5D6.02%20x%2010%5E%7B23%7D)
}[/tex]
Number of moles = ![\frac{4.21 x 10[tex]^{23}](https://tex.z-dn.net/?f=%5Cfrac%7B4.21%20x%2010%5Btex%5D%5E%7B23%7D)
}{
}[/tex]
Number of moles of CaCl₂ = 0.699moles
Learn more;
mole calculation brainly.com/question/13064292
#learnwithBrainly
