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Free_Kalibri [48]
3 years ago
9

Consider the dissolution of 1.50 grams of salt XY in 75.0 mL of water within a calorimeter. The temperature of the water decreas

ed by 0.93 oC. The heat capacity of the calorimeter is 42.2 J/oC. The density of the water (and the solution) is 1.00 g/mL. The specific heat capacity of the solution is 4.184 J/goC. Calculate the quantity of heat lost by the surroundings.
Chemistry
1 answer:
-BARSIC- [3]3 years ago
8 0

Answer:

The quantity of heat lost by the surroundings is 258,5J

Explanation:

The dissolution of salt XY is endothermic because the water temperature decreased.

The total heat consumed by the dissolution process is:

4,184 J/g°C × (75,0 + 1,50 g) × 0,93°C = 297,7 J

This heat is consumed by the calorimeter and by the surroundings.

The heat consumed by the calorimeter is:

42,2 J/°C × (0,93°C) = 39,2 J

That means that the quantity of heat lost by the surroundings is:

297,7J - 39,2J = <em>258,5 J</em>

I hope it helps!

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What word or two-word phrase best describes the shape of the fluoroform molecule?
Vlad [161]

Answer : The shape of the fluoroform molecule is Tetrahedral.

Explanation :

First we have to calculate the Hybridization of the molecule by formula,

\text{Number of electrons} = \frac{1}{2}[V+H-C+A]

where,

V = Number of valence shell electron in central atom

H = Number of neighboring monovalent atom

C = charge of cation

A = charge of anion

The central atom in this molecule is Carbon, it has 4 electrons in their valence shell.

The neighboring monovalent atoms are one Hydrogen atom and three Fluorine atom.

There is no charge of cation and anion on the given molecule.

V = 4

H = 1 Hydrogen atom + 3 fluorine atom = 4

C = 0

A = 0

By the above hybridization formula, we get

\text{Number of electrons}= \frac{1}{2}[4+4-0+0] = 4

The number of electron pair = 4

The number of lone pair = 0

The number of electrons is 4, this means that the hybridization is sp^{3} and the geometry of the molecule is Tetrahedral.

The geometry of the molecule is shown below.


3 0
3 years ago
Consider the following reaction at 298.15 K: Co(s)+Fe2+(aq,1.47 M)⟶Co2+(aq,0.33 M)+Fe(s) If the standard reduction potential for
fgiga [73]

Answer:

The correct answer is 0.186 V

Explanation:

The two hemirreactions are:

Reduction: Fe²⁺ + 2 e- → Fe(s)  

Oxidation : Co(s)  → Co²⁺ + 2 e-

Thus, we calculate the standard cell potential (Eº) from the difference between the reduction potentials of cobalt and iron, respectively,  as follows:

Eº = Eº(Fe²⁺/Fe(s)) - Eº(Co²⁺/Co(s)) = -0.28 V - (-0.447 V) = 0.167 V

Then, we use the Nernst equation to calculate the cell potential (E) at 298.15 K:

E= Eº - (0.0592 V/n) x log Q

Where:

n: number of electrons that are transferred in the reaction. In this case, n= 2.

Q: ratio between the concentrations of products over reactants, calculated as follows:

Q = \frac{ [Co^{2+} ]}{[Fe^{2+} ]} = \frac{0.33 M}{1.47 M} = 0.2244

Finally, we introduce Eº= 0.167 V, n= 2, Q=0.2244, to obtain E:

E= 0.167 V - (0.0592 V/2) x log (0.2244) = 0.186 V

4 0
4 years ago
Suppose that 98.0g of a non electrolyte is dissolved in 1.00kg of water. The freezing point of this solution is found to be -0.4
Sholpan [36]

Answer:

\large \boxed{\text{392 u}}

Explanation:

1. Calculate the molal concentration

The formula for the freezing point depression by a nonelectrolyte is

\Delta T_{f} = -K_{f}b\\b = -\dfrac{\Delta T_{f}}{ K_{f}} = -\dfrac{-0.465 \, ^{\circ}\text{C}}{\text{1.86 $\, ^{\circ}$C$\cdot$kg$\cdot$mol}^{-1}} = \text{0.250 mol/kg}

2. Calculate the moles of solute

\begin{array}{rcl}b & = & \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\\text{moles of solute} & = & b \times {\text{kilograms of solvent}}\\n & = &\text{0.250 mol/kg} \times \text{1.00 kg}\\ & = & \text{0.250 mol}\\\end{array}

3. Calculate the molecular mass

\begin{array}{rcl}\text{Moles} & = &\dfrac{\text{mass}}{\text{molar mass}}\\\\\text{0.250 mol} & = & \dfrac{\text{98.0 g}}{MM}\\\\MM & = & \dfrac{\text{98.0 g }}{\text{0.250 mol}}\\\\& = &\textbf{392 g/mol}\\\end{array}\\\text{The molecular mass of the solute is $\large \boxed{\textbf{392 u}}$}

3 0
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Which of the following statements holds true for a chemical change?
sp2606 [1]
A chemical change creates a new substance
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A chemist wants to extract copper metal from copper chloride solution. The chemist places 0.25 grams of aluminum foil in a solut
netineya [11]

Answer: About 0.20 grams of copper (II) is formed, and some aluminum is left in the reaction mixture

7 0
3 years ago
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