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uranmaximum [27]
3 years ago
7

Vitamin C, also known as ascorbic acid, is water soluble and cannot be produced by the human body. Each day, a person’s diet sho

uld include a source of vitamin C, such as orange juice. Ascorbic acid has a molecular formula of C6H8O6 and a gram-formula mass of 176 grams per mole.
Which formula represents the empirical formula for ascorbic acid?
Chemistry
1 answer:
Brilliant_brown [7]3 years ago
8 0
I wish I could help but I don't understand this problem if u need more help ask ur teacher or look for me help on this site
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Water and ammonium nitrate (NH4NO3) react in an endothermic reaction in a beaker. What would you expect to observe during this r
maksim [4K]

Answer:

The beaker will get colder

Explanation:

3 0
2 years ago
__________ have an electric charge of -1.60 × 10-19 C (-e).
nignag [31]

Answer:

Electrons have an electric charge of -1.60 × 10-19 C

Explanation:

Neutrinos and Neutrons have 0 e charge.

Protons have an electric charge of 1.60 × 10-19 C

Historically, electrons were assigned a negative charge

6 0
3 years ago
what is the formula used to find the heat energy for vaporization heat energy for fusion hrat energy for liquid
Alinara [238K]

Answer:

Use the formula q = m·ΔHv in which q = heat energy, m = mass, and ΔHv = heat of vaporization.

Explanation:

:)

8 0
3 years ago
How many molecules of CF₂Cl₂ are in 45.7 grams of CF₂Cl₂? (Show work)
posledela

Answer:

The answer to your question is: 2.20 x 10 ²³ molecules

Explanation:

Data

mass = 45.7 g

molecules of CF₂Cl₂ = ?

Process

1.- Calculate the mass number of CF₂Cl₂

   C = 12    F =2 x 19    Cl = 2 x 35.5

   total = 12 + 38 + 71

   total = 121 g

2.- Use the Avogradro's number to solve the problem

                       121 g -------------------  6.023 x 10²³ molecules of CF₂Cl₂

                        45.7 g ---------------     x

                        x = (45.7 x 6.023 x 10²³) / 121

                        x = 2.75 x 10²⁵ / 121

                        x = 2.20 x 10 ²³ molecules

4 0
3 years ago
A closed system initially containing 1×10^-3 hydrogen 2×10^-3M iodine at 448 degree Celsius and is allowed to reach equilibrium.
GaryK [48]

Answer:

Kc = 50.5

Explanation:

We determine the reaction:

H₂  +  I₂   ⇄   2HI

Initially we have 0.001 molesof H₂

and 0.002 moles of I₂

If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.

           H₂     +      I₂      ⇄   2HI

In:     0.001       0.002           -

R:       x                 x                2x

Eq:  0.001-x    0.002-x      0.00187  

x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted

So in the equilibrium we have:

0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵  moles of H₂

0.002 - 9.35×10⁻⁴ = 1.065×10⁻³ moles of I₂

Expression for Kc is =  (HI)² / (H₂) . (I₂)

0.00187 ² /  6.5×10⁻⁵ . 1.065×10⁻³ = 50.5

5 0
3 years ago
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