What is the value of h when the function is converted to vertex form?

Mathematics

2 answers:

Varvara68 [4.7K]3 years ago

8 0

Completing the squqre:

h(x) = x^2 - 8x + 14 = x^2 - 8x + 16 - 16 + 14 = (x-4)^2 - 2

Here h=4 and k = -2.

zloy xaker [14]3 years ago

7 0

$f(x)=ax^2+bx+c\\\\h=\dfrac{-b}{2a};\ k=f(h)$

We have:
$h(x)=x^2-8x+14\\\\a=1;\ b=-8;\ c=14$

Substitute:
$h=\dfrac{-(-8)}{2\cdot1}=\dfrac{8}{2}=4$

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