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Valentin [98]
3 years ago
14

A student mixes 2.83 mL of benzoyl chloride with excess 15 M NH4OH to produce 1.95 g of benzamide. What is the percent yield of

this student's experiment
Chemistry
1 answer:
andriy [413]3 years ago
7 0

Answer:

Explanation:

The reaction of benzoyl chloride with NH₄OH to produce benzamide is:

Benzoyl chloride + ammonia → Benzamide + NH₄Cl

Molar mass of benzoyl chloride: 140.57 g/mol. Density 1.21g/mL

Molar mass benzamide: 121.14g/mol.

To know percent yield you must know the theoretical yield of the reaction (How many grams are produced assuming a yield of 100%). Percent yield will be (Actual yield / Theoretical Yield) ₓ 100

Moles of 2.83mL of benzoyl chloride are:

2.83mL ₓ (1.21g/mL) ₓ (1mol / 140.57g) = 0.02436 moles of benzoyl chloride.

As 1 mole of benzoyl chloride produce 1 mole of benzamide (Theoretical yield), theoretical moles of benzamide produced are 0.02436. In mass:

0.02436 moles ₓ (121.14g / mol) = 2.95g of benzoyl chloride

As there are produced just 1.95, percent yield is:

(1.95g / 2.95g) ₓ 100 = 66.1%

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3 years ago
In a first–order reaction (A → B and rate = k [A]), tripling the concentration of A will have what effect on the reaction rate?
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Tripling the concentration of A will triple the reaction rate.

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5 0
4 years ago
A gaseous compound containing carbon and hydrogen was analyzed and found to consist of 83.65% carbon by mass. The molar mass of
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Answer:

The molecular formula is C6H14

Explanation:

Step 1: Data given

Suppose the mass of compound = 100 grams

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Hydrogen = 16.35 % = 16.35 grams

Atomic mass of carbon = 12.01 g/mol

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Step 2: Calculate moles

Moles = mass / molar mass

Moles carbon = 83.65 grams / 12.01 g/mol

Moles carbon = 6.965 moles

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Moles hydrogen = 16.19 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

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H = 16.19 moles / 6.965 moles = 2.33

This means for 1 mol C we have 2.33 moles H  OR for 3 moles C we have 7 moles H

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Step 4: Calculate molecular formula

We have to multiply the empirical formula by n

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7 0
4 years ago
Use the observation in the first column
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A. Substance C

A. Substance A  

Explanation:

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At 4 °C, Substance E has a vapor pressure of 86. torr and Substance F has a vapor pressure of 136. torr

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2.

Recall that :

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Substance C has an enthalpy of vaporization smaller than that of substance D. Then, substance C has a higher vapor pressure.

3.

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6 0
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